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daser333 [38]
3 years ago
15

There can only be 1 answer need help plzz

Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

do you like me yes or no

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WILL GIVE BRAINLIEST!!!
ELEN [110]

Answer:

C is the answer.  

Step-by-step explanation:

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3 years ago
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A discovery in New Jersey actually contributed to the
Butoxors [25]

Correct option is B. A discovery in New Jersey actually contributed to the

early economic development of America and, in 1714, a worker uncovered a green rock containing copper.

Here, the use of conjunction 'and' is incorrect as it creates a kind of distortion which seems as if we are talking about two different things: rather then linking the two parts of the sentence, 'and' further disconnects it.

"When" seems better than "And". It clearly indicates the mentioned time. Thus B is the correct answer.

To learn more about copper from given link

brainly.com/question/24856041

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4 0
2 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
Given two different circles O and Q, which of the following cases presents two circles with no (zero) common tangents?
borishaifa [10]
Concentric circles because if a line is tangent to one circle, it would only intersect teh other 
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Find<br>the<br>value<br>of sin 90+ tan45?<br>​
sashaice [31]

Answer:

91.61

Step-by-step explanation:

thats what i got

7 0
3 years ago
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