3 consecutive positive integers : x, x + 1, x + 2
x^2 = x + 2
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x + 1 = 0
x = -1....this is an extraneous solution that does not work
x - 2 = 0
x = 2
check...
square of the first = third
x^2 = x + 2
2^2 = 2 + 2
4 = 4 (correct)
so ur 3 integers are 2,3, and 4
For a shape to be perpendicular it must intersect and have right angles at 90 degrees. Trapezoids do not have this but acute and obtuse angles at their intersections. So the answer is no, the bases are not perpendicular. <span />
Answer:
umm sorry but i think you can do it im sure your smart go for it!
Step-by-step explanation:
Answer:
Y = 27
Step-by-step explanation:
To find the the value of y when x = 4 simply substitute the given value of x
into the equation and solve for y
Equation given: y - 3x = 15
x = 4 * substitute 4 for x in given equation *
y - 3(4) = 15
Now solve for y
simplify multiplication
y - 12 = 15
Add 12 to both sides
y - 12 + 12 = 15 + 12
y = 27
So we can conclude that when x = 4 y = 27
