The piecewise function is
f(x) = 2, 0 < x ≤ 1/2
f(x) = 2 + 0.7x, x > 1/2
<h3>How to determine the piecewise function?</h3>
From the question, we have:
Fares = $2.00 ⇒ up to (and including) 1/2 miles
Fares = $0.70 increment ⇒ greater than 1/2 miles
Let x represent the number of miles, and f(x) the fares.
So, we have:
f(x) = 2, 0 < x ≤ 1/2
f(x) = 2 + 0.7x, x > 1/2
The above represents the piecewise function
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Answer:
C= 1/(2ax+2aw)
Step-by-step explanation:
C=1/2x(a+w)
Multiply a and w by 2x. Take note of the sign.
C= 1/(2ax+2aw)
when writing your answer, you don't need the brakets. I just put them so you'd understand that all those characters in the bracket are the denominator.
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Answer:
1/36 = 0.02777...
Step-by-step explanation:
Given the sequence 1, 0.25, 0.111..., 0.0625, 0.04, you would like to know the next term.
<h3>Terms</h3>
We recognize the decimal values to be equivalent to ...
1, 1/4, 1/9, 1/16, 1/25
That is, they are the reciprocals of successive squares.
<h3>Next term</h3>
The next term will be the reciprocal of the 6th square:
1/36 = 0.02777...
The inverse of the given function 3x - 12 is determined as f⁻¹(x) = x/3 + 4.
<h3>
What is inverse of a function?</h3>
An inverse of a function is a function that serves to replace another function.
That is, if f(x) produces y, then putting y into the inverse of f produces the 0ut-put x .
Thus, an inverse function or an anti function is defined as a function, which can reverse into another function.
The inverse of the given function; f(x)= 3x − 12 is calculated as follows;
y = 3x - 12
replace y with x and x with y as shown below;
x = 3y - 12
now, solve for y
x + 12 = 3y
divide both sides of the equation by 3
x/3 + 12/3 = 3y/3
x/3 + 4 = y
f⁻¹(x) = x/3 + 4
Thus, the inverse of the given function 3x - 12 is determined as f⁻¹(x) = x/3 + 4.
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The complete question is written below:
find the inverse of the function, f(x) = 3x - 12
Answer:
The correct answer would be option C
Step-by-step explanation:
3^2*3^4*3^6=531441
3^12=531441
or for a simpler way you can just add the exponents together when the problem is set up like this
