The result of the respective questions are:
- This chi-square test only takes into consideration one variable.
- The type of chi-square test this is is a Goodness of Fit
- df= 3
- NO
<h3>How many variables are involved in the chi-square test?</h3>
a)
This chi-square test only takes into consideration one variable.
b)
The type of chi-square test this is, is a Goodness of Fit
To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.
The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.
c)
Parameter
n = 4
Therefore
Degrees of freedom
df= n - 1
df= 4 - 1
df= 3
d)
In conclusion
Parameters

df = 3
Hence
Critical value = 7.814728
Test statistic = 6.6
Test statistic < Critical value, .
NO, the result of this test is not statistically significant.
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Answer: Table D
Step-by-step explanation:
The coefficient of x^2 is -9, the coefficient of x is 7, and the constant is 0, so we know a = -9, b = 7, c = 0.
- This eliminates tables A, B, and C.
Thus, table D is the answer.
Answer:
Each octave change requires a doubling of the frequency.
Therefore, one octave above 126.63 is 126.63 * 2 which equals
253.26
Step-by-step explanation: