All categories

3 years ago

Show some different ways to make 7,502

Mathematics

2 answers:

Greeley [361]3 years ago

5 0

.........................

PilotLPTM [1.2K]3 years ago

3 0

750 tens and 2 ones and for the bottom 7502 ones

You might be interested in

1. In triangle ABC, m∠A=36, and m∠C=12. Calculate m∠B.

ki77a [65]

Answer:

1) m ∠B = 132°

2) m ∠B = 113°

Step-by-step explanation:

1. In triangle ABC, m ∠A=36, and m ∠C=12. Calculate m ∠B.

We are given measure of 2 angles and we need to find the third angle.

We know that, sum of angles of triangle = 180°

We can write as:

∠A + ∠B + ∠C = 180°

Now put m ∠A=36 and m ∠C=12, to find m ∠B

$\angle A + \angle B + \angle C = 180\\36+ \angle B +12=180\\\angle B+48=180\\\angle B=180-48\\\angle B=132$

So, we get m ∠B = 132°

2. In triangle ABC, m ∠A=40, and m ∠C=27. Calculate m ∠B.

We are given measure of 2 angles and we need to find the third angle.

We know that, sum of angles of triangle = 180°

We can write as:

∠A + ∠B + ∠C = 180°

Now put m ∠A=40 and m ∠C=27, to find m ∠B

$\angle A + \angle B + \angle C = 180\\40+ \angle B +27=180\\\angle B+67=180\\\angle B=180-67\\\angle B=113$

So, we get m ∠B = 113°

6 0

4 years ago

A kids skipping rope is 7ft long. How many ropes could I cut from a 10 yard long piece of rope?

Hatshy [7]

3 feet are in one yard
so 3 ×10 =30
so 30 ÷ 7 = 4.2
Answer is 4
even is there if there is a decimal only 4 can be made

7 0

3 years ago

A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil

Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

$P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......$

where, n = number of trials (samples) taken = 20 children

r = number of success = none of the 20 children

p = probability of success which in our case is probability that

children are unvaccinated, i.e; p = 13.5%

Let X = Number of children that are unvaccinated

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

P(X = 0) = $\binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}$

= $1\times 1 \times 0.865^{20}$

= 0.055

Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

8 0

4 years ago

Which statement proves that F(x) is an exponential function

Alex_Xolod [135]

Answer:

Y=a*b^x

If xponent is a variable

Step-by-step explanation:

4 0

3 years ago

If dy/dx = x^2 + 4 what is the value of y

ad-work [718]

Answer:

y = (1/3)x^3 +4x + c . . . . . for some constant c

Step-by-step explanation:

The anti-derivative of x^n is (x^(n+1))/(n+1). Applying this rule to each of the terms in dy/dx, we get ...

y = (1/3)x^3 + 4x

There may be an added constant as well, conventionally represented by "c".

y = (1/3)x^3 +4x +c

7 0

4 years ago