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koban [17]
3 years ago
11

What happens when the scale factor is negative?

Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0
That menas that it we be negative because any thing that is negative is going bigger 
madreJ [45]3 years ago
6 0
<span>The geometric shapes are decrease, if the scale factor is negative.

</span><span> The negative scale factor is also a factor in which the area of the different geometric shapes get reduced or the objects gets inverted. The area of the different geometric objects is negative due to the negative scale factor.</span>
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o-na [289]

Answer:

creating shapes,angles and lines

4 0
3 years ago
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If a fair 20 sided die is rolling, what is the probability of rolling a number greater than 10?
KIM [24]

Answer:

10/20

<h2><em>Please mark as brainliest answer!!!</em></h2>
8 0
3 years ago
Exercise 3 Iron Man is checking out a new suit that fires lasers more accurately. If he is aiming for a bullseye, his original s
Novosadov [1.4K]

Answer: (a). insufficient evidence.

(b). sufficient evidence

(c). insufficient evidence

Step-by-step explanation:

we will analyse this carefully to help us understand it better.

we have the standard deviation for the original suit = 2mm

standard deviation for new suit = 1.6mm

given n = 1.6

from the question we know that  the  suit with less standard deviation is better than the other suit

considering a null hypothesis;

H₀ : б ≥ 2, (here the new suit is not better than the original alternative hypothesis).

Also Hi : б < 2 (we have here that the new suit is better than the original )

using the Chi-Square distribution with n-1 degree of freedom to test the claim about the value of the standard deviation;

X² = (n-1) s²/ б² = (16-1)(1.6)² / (2)² = 9.6

taking the P value of X² (9.6) for 15 D O F  from the P value table gives us

1-0.8441 = 0.1559

also ∝ = 0.05

where P-value > ∝ (0.05)

we can see from here that there is insufficient evidence to claim that new suit is better than that of the original suit, having failed to neglect H₀

(b). Given n = 100 and s = 1.6

then we have that X² = (n-1) s²/ б² = (100-1)(1.6)² / (2)² = 63.36

P-value of X² at 99 dif gives 0.0020

where ∝ = 0.05

since P value < ∝

rejecting the null hypothesis H₀,

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(c). where we have that ∝ = 0.001

for part(b) P-values = 0.0020

given P-value > ∝ ;

we fail to neglect the null hypothesis.

From this we can say that the is insufficient evidence backing the claim thhat the new suit is better than the original suit at 99.99% confidence level.

cheers i hope this helps!!!!!

5 0
4 years ago
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Andrews [41]
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