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3 years ago

Geometry math question

Mathematics

2 answers:

g100num [7]3 years ago

8 0

we can see that

Z , L and S are three points of line ZS

so, Z , L and S are collinear

and

Z , L and S lie on plane M

so, they are coplanar

so, option-C....................Answer

elixir [45]3 years ago

5 0

we can see that

Z , L and S are three points of line ZS

so, Z , L and S are collinear

and

Z , L and S lie on plane M

so, they are coplanar

so, option-C....................Answer

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For every team competing in a robotics competition, there are 4 students. How many students are on 3 teams?

givi [52]

Answer:

There are 12 students.

Step-by-step explanation:

This is because there are 4 students per team, and there is 3 teams.

So...

3 * 4 = 12 students

8 0

3 years ago

Need help ASAP !!! <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B18%20%5Ctimes%2018%20%5Ctimes%204%7D%20" id="TexFor

VashaNatasha [74]

Answer:

Step-by-step explanation:

The first step to solving this equation is multiplying. Multiply the numbers on the inside of the square root.

18 × 18 × 4 = 1296

Now, you are going to find the square root of 1296.

$\sqrt{1296}$ = 36

You now have your final answer.

I hope this makes sense and is easy to understand. Please let me know if you need any more help. Have a great day! :]

3 0

3 years ago

Read 2 more answers

Consider the algebraic expression:

o-na [289]

Answer:

where is the expression??

7 0

3 years ago

Read 2 more answers

Richard has just been given an l0-question multiple-choice quiz in his history class. Each question has five answers, of which o

myrzilka [38]

Answer:

a) 0.0000001024 probability that he will answer all questions correctly.

b) 0.1074 = 10.74% probability that he will answer all questions incorrectly

c) 0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

d) 0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Each question has five answers, of which only one is correct

This means that the probability of correctly answering a question guessing is $p = \frac{1}{5} = 0.2$

10 questions.

This means that $n = 10$

A) What is the probability that he will answer all questions correctly?

This is $P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} = 0.0000001024$

0.0000001024 probability that he will answer all questions correctly.

B) What is the probability that he will answer all questions incorrectly?

None correctly, so $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074$

0.1074 = 10.74% probability that he will answer all questions incorrectly

C) What is the probability that he will answer at least one of the questions correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

Since $P(X = 0) = 0.1074$ , from item b.

$P(X \geq 1) = 1 - 0.1074 = 0.8926$

0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

D) What is the probability that Richard will answer at least half the questions correctly?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.2)^{5}.(0.8)^{5} = 0.0264$

$P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055$

$P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008$

$P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001$

$P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0$

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0264 + 0.0055 + 0.0008 + 0.0001 + 0 + 0 = 0.0328$

0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

8 0

3 years ago

Its on the picture, plz go fast

Naily [24]

Answer:

Elimination

Step-by-step explanation:

You would not do substitution since it would not work so you do elimination since the 4y and -4y eliminate then you just solve for it.

7 0

2 years ago