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2 years ago

PLEASE HELP MEE

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

5 0

Answer:

Option A= 250

Step-by-step explanation:

Coterminal angles are angles in standard positions having thesame terminal .

Coterminal angles are always negative and positive.

For example:

The coterminal angle of 30° is-

30 - 360 = -330

30 + 360 = 390

Therefore, -330 and 390 are coterminal.

So, to the question:

The angles between 0 -360 coterminal to -110 is 250.

Prove:

250 - 360 = -110

250 + 360 = 610

Option A is correct

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Because 60 degrees is half of 30 degrees

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Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y

mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

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Step-by-step explanation:

Given the data in the question;

y = $y = e^{(x - 1 )$ , y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = $y = e_2}^{(x - 1 )_$ , y = 0

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx$

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2 dx$

Volume = $\pi \int\limits^2_1 e^{2x-2}dx$

Volume = $\frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx$

Volume = $\frac{\pi }{e^2} [\frac{e^{2x}}{2}]^2_1$

Volume = $\frac{\pi }{2e^2} [e^4 - e^2 ]$

Volume = $\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

$\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

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