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3 years ago

What is the area of the triangle formed from (0,-1) (0,-4) (4,-1)

Mathematics

2 answers:

bogdanovich [222]3 years ago

6 0

Area of the triangle = (1/2)(base)(height) = (1/2)(4)(5) = 10 square units.
The correct answer is A.

rusak2 [61]3 years ago

4 0

Answer:

Step-by-step explanation:

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Help me please i do not understand it.

sergij07 [2.7K]

Answer:y = 2x + 4

Explanation:

1) The slope - intercept form is of the kind y = mx + b, where m is the slope and b is the y-intercept.

2) Given two points you can find the slope (using the two points) and then the equation using one of the points.

3) slope = m = Δy / Δx

points given (3,10) , (0,4)

m = [y2 - y1] / [x2 - x1] = [10 - 4] / [3 - 0] = 6 / 3 = 2

4) equation

y - y2
-------- = m
x - x2

y - 4
---------- = 2
x - 0

=> y - 4 = 2 (x - 0)

y - 4 = 2x

y = 2x + 4

3 0

3 years ago

Which ordered pair is a solution of the equation below? y=-7+2x?

Maru [420]

The answer to this question is:
x y
(1,-5) so the equation would be -5=-7+2(1)
-5=-7+2 -7+2=-5
-5=-5
hope this helps;)

8 0

2 years ago

Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0

gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

$y'+6y/t = t-1+1/t$

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/t $e^(\int 1/tdt) = t$

So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

siubstitute y(1) = 16

$16 = 16^3/3-128+1+C\\C = -1206$

4 0

3 years ago

Georgianna claims that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

Allisa [31]

Answer:

The condition are

The Null hypothesis is $H_o : \mu = 5$

The Alternative hypothesis is $H_a : \mu < 5$

The check revealed that

There is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 5 \ year$

The sample size is n = 20

The sample mean is $\= x = 4.6 \ years$

The standard deviation is $\sigma = 2.2 \ years$

The Null hypothesis is $H_o : \mu = 5$

The Alternative hypothesis is $H_a : \mu < 5$

So i will be making use of $\alpha = 0.05$ level of significance to test this claim

The critical value of $\alpha$ from the normal distribution table is $Z_\alpha = 1.645$

Generally the test statistics is mathematically evaluated as

$t = \frac{\= x - \mu}{ \frac{\sigma }{\sqrt{n} } }$

substituting values

$t = \frac{ 4.6 - 5}{ \frac{2.2}{\sqrt{20} } }$

$t = -0.8131$

Looking at the value of t and $Z_{\alpha }$ we see that $t < Z_{\alpha }$ so we fail to reject the null hypothesis

This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

4 0

2 years ago

2x +5y=10 writing equations in slope intercept form

rosijanka [135]

Answer: y=-2/5x+2

Solving Steps:
2x+5y=10 - Move the variable to the right
5y=10-2x - Divide both sides by five
y=2-2/5x - Reorder the terms
y=-2/5x+2

7 0

3 years ago