Answer:
b
Step-by-step explanation:
Answer:
the inverse for each relation:
1. {(1,-2), (2, 3),(3, -3),(4, 2)} is
<u>{</u><u>(</u><u>-</u><u>2</u><u>,</u><u>1</u><u>)</u><u>,</u><u>(</u><u>3</u><u>,</u><u>2</u><u>)</u><u>,</u><u>(</u><u>-</u><u>3</u><u>,</u><u>3</u><u>)</u><u>,</u><u>(</u><u>2</u><u>,</u><u>4</u><u>)</u><u>}</u><u>.</u>
Answer:
hi! i dont have the answer because i suck at school lol XD but, i actually have the same question! do you know the answer yet?:] sorry to bother you if you dont.
Step-by-step explanation:
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer:
In 25% of the games at least 55 points were scored.
Step-by-step explanation:
Percentage:
Number of desired outcomes multiplied by 100 and divided by the number of total outcomes.
In this question:
8 total games
In 2 at least 55 were scores.
100*2/8 = 100/4 = 25%
In 25% of the games at least 55 points were scored.
