1/2 to the fifth power in fraction form

Complete the point-slope equation of the line through (2,3)(2,3)left parenthesis, 2, comma, 3, right parenthesis and (7,4)(7,4)l

vovikov84 [41]

Answer:

$y = \frac{1}{5}x +\frac{13}{5}$

Step-by-step explanation:

Given

$(x_1,y_1) = (2,3)$

$(x_2,y_2) = (7,4)$

Required

Complete the equation y - 4.....

First, we need to determine the slope as follows:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{4 - 3}{7 - 2}$

$m = \frac{1}{5}$

The equation is then calculated as thus:

$y - y_1 = m(x - x_1)$

This gives:

$y - 4 = \frac{1}{5}(x -7)$

Open bracket

$y - 4 = \frac{1}{5}x -\frac{7}{5}$

Add 4 to both sides

$y - 4 +4= \frac{1}{5}x -\frac{7}{5} + 4$

$y = \frac{1}{5}x -\frac{7}{5} + 4$

$y = \frac{1}{5}x +\frac{-7+20}{5}$

$y = \frac{1}{5}x +\frac{13}{5}$

6 0

3 years ago

Here someone help me is this correct or no someone reported me saying it was wrong

Neko [114]

$-2^{4} = 16$

You're right.

8 0

3 years ago

Read 2 more answers

Consider circle O. If AE = 7, EC = 2, and BE = 4, what is ED?

miv72 [106K]

The correct answer is 3.5

Two chords AC and BD are intersecting inside the circle. The Intersecting Chord Theorem states that when two chords intersect inside a circle, the products of their segments are equal.

Thus, for the given circle:
(AE) × (EC) = (BE) × (ED)

The lengths of the segments are
AE = 7
EC = 2
BE = 4
ED = ?

To solve for ED, we simply substitute the known values into the equation
$ED = \frac{7(2)}{4} = \frac{14}{4} = 3.5$

6 0

3 years ago

Read 2 more answers

What is 1 +1 pls HELP

ElenaW [278]

Answer:

2

Step-by-step explanation:

Subject: Re: Need the math proof for 1 + 1 = 2

The proof starts from the Peano Postulates, which define the natural

numbers N. N is the smallest set satisfying these postulates:

P1. 1 is in N.

P2. If x is in N, then its "successor" x' is in N.

P3. There is no x such that x' = 1.

P4. If x isn't 1, then there is a y in N such that y' = x.

P5. If S is a subset of N, 1 is in S, and the implication

(x in S => x' in S) holds, then S = N.

Then you have to define addition recursively:

Def: Let a and b be in N. If b = 1, then define a + b = a'

(using P1 and P2). If b isn't 1, then let c' = b, with c in N

(using P4), and define a + b = (a + c)'.

Then you have to define 2:

Def: 2 = 1'

2 is in N by P1, P2, and the definition of 2.

Theorem: 1 + 1 = 2

Proof: Use the first part of the definition of + with a = b = 1.

Then 1 + 1 = 1' = 2 Q.E.D.

Note: There is an alternate formulation of the Peano Postulates which

replaces 1 with 0 in P1, P3, P4, and P5. Then you have to change the

definition of addition to this:

Def: Let a and b be in N. If b = 0, then define a + b = a.

If b isn't 0, then let c' = b, with c in N, and define

a + b = (a + c)'.

You also have to define 1 = 0', and 2 = 1'. Then the proof of the

Theorem above is a little different:

Proof: Use the second part of the definition of + first:

1 + 1 = (1 + 0)'

Now use the first part of the definition of + on the sum in

parentheses: 1 + 1 = (1)' = 1' = 2 Q.E.D.

3 0

3 years ago

Solve for U 11=8+u/7.68

BlackZzzverrR [31]

$\begin{gathered}\\ \sf\longmapsto 11=\frac{8+u}{7.68}\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 11 = \frac{8 + u}{ \frac{192}{25} } \end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 11=\frac{(8+u)×25}{192}\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 11=\frac{200+25u}{192}\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2112=200+25u\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2112-25u=200\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -25u=200-2112\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -25u=-1912\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto u=\frac{1912}{25}\end{gathered}$

Alternate form:

u=76.48

7 0

2 years ago