A: <span>(–2, 12), (0,0), and (2, –12)</span>
Answer:
No solution
Step-by-step explanation:
Answer:
C. (-3,11)
Step-by-step explanation:
Tp is (-3,6) implies the quadratic could have been
f(x) = (x+3)²+6
(2/3)f(x) = (2/3)[(x+3)²+6]
= (2/3)(x+3)²+4
(2/3)f(x)+3 = (2/3)(x+3)²+4+3
= (2/3)(x+3)²+7
Tp at (-3,7)
Alternately,
No change in domain so x remains-3
(2/3)f(x) changes y from 6 to 4 (6×2/3)
+3 increases the y by 3
i.e 4+3 = 7
So, (-3,7)
this can be solve using the formulaP = rghwhere P is the total pressurer is the densityh is the heightg is the acceleration due to gravity
fist solve the total pressureP = 1.5 bar + 1 barP = 2.5 barP = 250,000 Pa
P = rgh250,000 = (997)(9.81)hh =25.56 m
Answer:
thats a great question
Step-by-step explanation:
