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2 years ago

1/2 to the fifth power in fraction form

Mathematics

1 answer:

morpeh [17]2 years ago

4 0

1/32 is the answer for the question

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Answer for the problem of 2 1/5+1 3/4

lions [1.4K]

The answer to this question is 3 19/20

4 0

3 years ago

Write the equation of the line graphed below.

posledela

Answer:

y=2x +3

Step-by-step explanation:

The slope hits the points (-1,2) and (0,2). If you count how many units are right and up, then that's your slope. In this case, the distance between those two points are 1 right and 2 up which is the same thing as 2. The y-intercept is 3 since the slope crosses the y-axis there.

6 0

2 years ago

Help please. Solve the system of equations using substitution. Show your work in the workspace provided below.

LenKa [72]

Answer:

x=0 y=-11 (0,-11)

Step-by-step explanation:

1. take what y equals (3x-11) and plug it in for y in the second equation

Should look like this: O= 6x-2(3x-11)-22

2. Then distribute O=6x-6x+22-22

3. Then combine like terms O= 0 the 22's cancel out as well as the x's

x= 0

4. plug 0 in for x in the first equation y=3(0)-11

5. y= -11

6. x=0 y=-11 (0,-11)

6 0

3 years ago

Matt reasoned that he can write 9/1,000 as 0.9. Is he correct? Explain your answer.

GuDViN [60]

No because 9/1,000 in decimals would be 0.009 because if the number was a 3 number then it would go in the tenths

5 0

3 years ago

In an experiment, some diseased mice were randomly divided into two groups. One group was given an experimental drug, and one wa

damaskus [11]

Answer:

D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.

Step-by-step explanation:

We will test the hypothesis on the difference between means.

We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).

Then, the difference between means is:

$M_d=M_1-M_2=18.2-15.9=2.3$

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{2.3-(0)}{1.1}=2.09$

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.

This is approximately 2 standards deviation (z=2).

The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.

4 0

3 years ago