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Vikentia [17]
3 years ago
5

For the functions f(x) = 2x − 6 and g(x) = 5x + 1, which composition produces the greatest output?

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

g(x) = 5x + 1

Step-by-step explanation:

Given data

We have the following expressions to work with

f(x) = 2x − 6 and

g(x) = 5x + 1

say the value of x = 3

let us put x into the two expressions above and compare the output

f(x) = 2*3 − 6= 6-6= 0

g(x) = 5*3 + 1= 15+1= 16

Hence the second function has the greatest output

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Describe how you could represent the fraction 4/10 using a model or number line
zubka84 [21]

Answer:

Not going to give answer, but let you solve

Step-by-step explanation:

You first have to start by drawing a number line and mark two integers between the fraction lines. Then you have to divide the section between the two integers in an equal number of parts which is equal to the denominator.

Hope I helped

5 0
2 years ago
Solve for all values of x by factoring. x^2+3x+8=-3x+3
docker41 [41]

Answer:

x = -1,-5

Step-by-step explanation:

X^2 + 3x + 5 = -3x

x^2 + 6x + 5 = 0

(x + 5)(x + 1) = 0

x = -1,-5

6 0
3 years ago
2/x-1=3/3x-3+1/6<br> Please solve for x
sweet [91]

Answer:

1y

Step-by-step explanation:

3 0
3 years ago
An unfair coin with .4 probability of tails is flipped 7 times what is the probability of obtaining exactly 5 heads
steposvetlana [31]
P(heads) = 1 - 0.4 = 0.6P(5\ heads)=7C5\times0.6^{5}\times0.4^{2}=0.2613
The answer is 0.26 to 2 d.p.
5 0
3 years ago
When two six-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is not 5.
zaharov [31]

Answer:

p(Not\ 5) = \frac{8}{9}

Step-by-step explanation:

Given:

Txo six-sided dice are rolled.

Total number of outcomes n(S) = 36

We need to find the probability that the sum is not equal to 5 p(Not 5).

Solution:

Using probability formula.

P(E)=\frac{n(E)}{n(S)}  ----------------(1)

Where:

n(E) is the number of outcomes favourable to E.

n(S) is the total number of equally likely outcomes.

The sum of two six-sided dice roll outcome is equal to 5 as.

Outcome as 5: {(1,4), (2,3), (3,2), (4,1)}

So, the total favourable events n(E) = 4

Now, we substitute n(E) and n(s) in equation 1.

P(5)=\frac{4}{36}

p(5) = \frac{1}{9}

Using formula.

p(Not\ E) + p(E) = 1

p(Not\ 5) + p(5) = 1

Now we substitute p(5) in above equation.

p(Not\ 5) + \frac{1}{9} = 1

p(Not\ 5) = 1-\frac{1}{9}

p(Not\ 5) = \frac{9-1}{9}

p(Not\ 5) = \frac{8}{9}

Therefore, the sum of two six-sided dice roll outcome is not equal to 5.

p(Not\ 5) = \frac{8}{9}

6 0
3 years ago
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