Answer:
<u>37/8</u>
Step-by-step explanation:
we are going to create 5 1/2 into an improper fraction for now, so it is easier to manipulate.
5 1/2 = 11/10
in order to find the answer, we need to set them both to a common denominator(we need to make sure they have the same denominator so it is easier to subtract)
11/2 if we just take 1 of the cups that Abby made and subtract that by 7/8 that give us the answer
11/2 - 1 = 9/2
we will now us the cup we subtracted from that and "give it to the kids"
1 = 8/8
so
8/8 - 7/8 = 1/8
so we have 1/8 leftover from that cup, so we can add that back
since 1/8 is a hard number to just add off the top of your head, we can just change the denominator of 9/2 into 8 instead of 2:
9/2 = 36/8
so
1/8 + 36/8 = 37/8
so since 37/8 cannot be simplified anymore, the answer is
<u>37/8</u>
Answer:
No, the law of large numbers says that the proportion of yellow cards should approach the true probability after many trials.
Step-by-step explanation:
∠1 is an angle formed by the two lines PF and YF at point F
We can also call this angle as ∠PFY because it indicates the point F in the middle where the angle is formed
We can call this angle as ∠YFP because it also indicates the point F in the middle where the angle is formed
we can also call this angle ∠F since F is the point where the angle is formed.
Correct answer: ∠PFY, ∠YFP, ∠F
Answer:
Choice D.
Step-by-step explanation:
The range is the set of all y-coordinates of the points in the graph.
The graph is a wavy function that has a maximum y-coordinate of 1 and a minimum y-coordinate of -1. The y-coordinates can also be all numbers between -1 and 1. Choice A. is only the two numbers -1 and 1. That is not correct since the range comprises the numbers -1, 1, and all numbers in between -1 and 1.
Answer: Choice D.
because the symbol is a less than sign < the blue area needs to be below the red line and does not include the solution to Y ( if it included Y it would be a ≤ symbol.
When the solution isn't included, it is a dashed line.
so the answer would be D
