Let x be the first digit.
Let y be the second digit.
Let z be the third digit.
x+y+z=18
y= (-2)(-4)
y= 8
x= 3^2
x= 9
Therefore z=1.
The number is
= 100x+10y+z
= 100(9)+10(8)+(1)
= 981
Answer:
Sn
<em>Your</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>Option</em><em> </em><em>A</em><em> </em><em>.</em>
<span>x cubed +3x squared - 4x= 0
= x^3 + 3x^2 -4x = 0
=x(x^2 +3x -4) = 0
= x (x+4)(x-1) = 0
x = 0
x+ 4 = 0 then x = -4
x - 1 = 0 then x = 1
answer: x = 0, x = -4 and x = 1</span>
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