Answer: choice B) a35 = -118
=====================================================
Explanation:
When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get
an = a1+d(n-1)
32 = a1+d(5-1)
32 = a1+4d
Solve for a1 by subtracting 4d from both sides
a1 = 32-4d
We'll plug this in later
Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula
an = a1+d(n-1)
7 = a1 + d(10-1)
7 = a1+9d
Now substitute in the equation in which we solved for a1
7 = a1+9d
7 = 32-4d+9d ... replace a1 with 32-4d
7 = 32+5d
5d = 7-32
5d = -25
d = -25/5
d = -5
This tells us that we subtract 5 from each term to get the next term.
Use this d value to find a1
a1 = 32-4d
a1 = 32-4*(-5)
a1 = 32+20
a1 = 52
The first term is 52
--------------
The nth term formula is therefore
an = 52 + (-5)(n-1)
which simplifies to
an = -5n + 57
To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.
--------------
Replace n with 35 to find the 35th term
an = -5n + 57
a35 = -5(35) + 57
a35 = -175 + 57
a35 = -118
Find the interquartile range of 17, 23, 8, 5, 9, 16, 22, 11, 13, 15, 17, 18
Yuri [45]
8.25
Hope I helped! ( Smiles )
Answer:
Option D. 5890.5 feet²
Step-by-step explanation:
An individual head of a sprinkler system covers a circular are of grass with a radius of 25 feet.
Yard has three sprinkler heads that each cover circular area with no overlap.
We have to calculate the approximate area watered by these 3 sprinkler heads.
Area covered by one sprinkler = π×r² = π×(25)² = 625π feet²
Therefore area covered by three sprinkler heads = 3 × 625π = 5892.85 feet²
which matches the approximate value of Option D. 5890.5 feet²
A) 144 degrees since it would be 72 x 2 I think
Answer:
80
Step-by-step explanation:
From the given diagram;
KN = NM
9x - 5 = 7x + 7
9x - 7x = 7 + 5
2x = 12
x = 12/2
x = 6
Since KM= 2KL
KM = 2(6x+4)
KM = 12x + 8
KM = 12(6)+8
KM = 72+8
KM = 80
Hence the length of KM is 80
