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vichka [17]
3 years ago
10

I need help pleaseeeee

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0
2.1 ÷ 1.488 = 1.41
1.41 rounded to the nearest tenth is 1.4
so your answer is 1.4
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Putting the values, we get,  

t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314  

14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)  

is the required confidence interval for the true mean length of rods.

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