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3 years ago

I can't seem to figure this question out. I've worked it out but I keep getting stuck

Mathematics

1 answer:

olasank [31]3 years ago

4 0

We know X=-20 because -20+4 over -3 = 6 then all we have to do is 6 - -20 = 26

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PLEASE HELP ME<br> Answer the question in the picture.

Sati [7]

Answer:

3^-2=1/9

3^0=1

3^1=3

3^2=9

7 0

3 years ago

Read 2 more answers

Please help with 6 and 7

Ilya [14]

Answer:

6. The number is $-5$

7. The two numbers are $10$ and $11$

Step-by-step explanation:

Question six can be re-worded to create the following expression:

$-2=\frac{4x+10}{5}$

Solve for x to find the number:

$-2=\frac{4x+10}{5}\\-10=4x+10\\-20=4x\\\frac{-20}{4} = x\\-5 = x$

Question seven can be solved by first listing the constraints (assuming x is smaller than y):

x and y are less than 20
$x + 1 = y$
$3x - 8 = 2y$

To get the numbers, we can create a system of linear equations. First, solve for $y$ in each expression:

$y = x+1$

$2y = 3x-8\\y = \frac{3}{2}x - 4$

Solve for $x$ :

$x+ 1 = \frac{3}{2}x - 4\\x + 5 = \frac{3}{2}x\\5 = \frac{3}{2}x - x\\5 = \frac{1}{2}x\\10 = x$

Solve for $y$ :

$y = x + 1\\y = 10 + 1\\y= 11$

4 0

2 years ago

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What is 1/5 + 3/10 ??

Anarel [89]

Answer:

first we will make them like fractions

so 1/5= 2/10 so it will be

2/10+3/10= 5/10

HOPE IT HELPS

mark as brainliest

7 0

3 years ago

Solve the equation for an ellipse for y. Assume that y > 0. y^2/a^2 + x^2/b^2 = 1

In-s [12.5K]

Multiply each term by a^2b^2:-

b^2y^2 + a^2x^2 = a^2b^2
subtract a^2x^2 from both sides
b^2y^2 = a^2b^2 - a^2x^2
Now divide both sides by b^2

y^2 = a^2 - a^2x^2 / b^2 = a^2 (1 - x^2/b^2)

take positive square root ( because y > 0)

y = a sqrt(1 - x^2/b^2)

4 0

3 years ago

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Please help me it is due in 10 minutes

MAXImum [283]

Answer:

whooops no one had answered u from 50 min!

3 0

3 years ago