Answer:
The probability is 0.3576
Step-by-step explanation:
The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.
For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773
To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649
The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.
As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576
130.95 rounded to the nearest tenths place is 131.0
A five or above means you round up.
1) Point A will be at (-4,4)
2) I think an equilateral triangle can't be right triangle
The perimeter , width and length are all one dimensional so the preimeter of the resulting rectangle will be 2.5 * 36 = 90.
The area is 2 dimensional whereas the vase and height are one dimensional so the area will be increased by a factor of 5^2 ( or 25)
New rea = 36*25 = 900
solids are 3 dimensional so the ratio of thereir volumes is 5^3 : 3^3
= 125:27
to answer the last 2 use the formula Volume = pi r^2 h where r = radius and h = height of a cylinder
