Answer:
A - Stigma
B - Anther
C - Filament
D - Style
E - Ovary
F - Petal
Explanation:
The above are the correct answers of the image drawn in the attachment.
These are parts of a flower.
A - Stigma: It is the head of the pistil. It contains a sticky substance that catches pollen grains from other pollinators.
B - Anther: This is the head of the stamen. It produces pollen grain.
C - Filament: It is a long slender part of the flower. It attaches the anther to the flower.
D - Style: It actually holds the stigma.
E - Ovary: It holds the ovule. Found at the base of the pistil.
F - Petal: It attracts pollinators to the flower.
<span>The reaction
that takes place in the stroma is collectively known as the Calvin Cycle. The
stroma is responsible for the 2nd stage of photosynthesis where ATP
and NADPH are used to capture and reduce carbon dioxide in the plant cell.</span>
<span>
It is a fluid-like organelle that surrounds the grana within the
chloroplast in plant cells. The stroma is also responsible for storing
chloroplast DNA and chloroplast ribosomes where molecular processes like
replication and transcription/translation of chloroplast proteins occur.</span>
The reduced coenzymes generated by the citric acid cycle donate electrons in a series of reactions called the electron transport chain. The answers are as;
a) 1. NADH and 7. FADH2
b) 6. O2
c) 3. NAD+, 1. H2O, 4. ATP and 8. FAD
Oxygen is the ultimate electron acceptor, and it combines with hydrogen ions to produce H2O. This process occurs at the conclusion of the electron transport process.
ATP molecules, which are carriers of energy, would be the final outcome of the oxidative phosphorylation process.
(a) NADH and FADH2 donate electrons to the electron transport chain.
(b) O2 is the final electron acceptor.
(c) NAD+, H2O, ATP, and FAD are the final products of the electron transport chain and oxidative phosphorylation.
You can also learn about oxidative phosphorylation from the following question:
brainly.com/question/29104155
#SPJ4
Answer:
Explanation:
From the question, the total population = 171 i.e (80+71+21)
Genetic frequency therefore; BB = 71/171 = 0.42
Bb = 80/171 = 0.47
bb = 20/171 = 0.12
Allele frequency therefore;
Allele B = 0.42+(0.50×0.47) = 0.66
Allele b = (0.50×0.47)+0.12 = 0.36
Note all values were rounded up to two significant figures
Answer:
bacteria
Explanation:
Thats just an assumption. I may be wrong but I think its bacteria.
