For this case we have the following equation:
y = 2x - 2
For the point (1, 0) we have:
x = 1
y = 0
Substituting values we have:
0 = 2 (1) - 2
0 = 2 - 2
0 = 0
We observe that equality is fulfilled and therefore, the point belongs to the equation.
Answer:
b. (1, 0)
Answer:
A is correct
Step-by-step explanation:
With a given parallel line and a given point on the line
we can use the point-line method: y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.
Here
m=-10, k=-5, (x0,y0)=(-3,5)
=> the required line L is given by:
L: y-5=-10(x-(-3))
on simplification
L: y=-10x-30+5
L: y=-10x-25
Answer:
The digit that is in the TENS place is 5
Step-by-step explanation:
