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ivann1987 [24]
3 years ago
15

John made a kite with all four sides the same length, as shown below. What is the perimeter of the kite?

Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

There's no images attached

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Ahhhhhhhhhhhhhhhhhhhhhhh
Bess [88]

Answer:

Its 9

Step-by-step explanation:

I did this in 5th grade... All you gotta do is count and there's 4 in the bottom aka 2 rows of 4 and there's 1 block on the top its 9

4+4+1=9

4+4=8

Add a 1 etc.

5 0
3 years ago
A rectangular prism has a length of 6 meters, a height of 8 meters, and a width of 5 meters. What is its volume, in cubic meters
KiRa [710]

Answer:

240

Step-by-step explanation:

length x width x height

6 x 5 x 8

7 0
2 years ago
Read 2 more answers
Given ​ f(x) = x^2 − 2x − 5​.
lukranit [14]

Answer:

(x - 1)^2 - 6

Step-by-step explanation:

You need to know:

Vertex form = a(x -h)^2 + k

The vertex is at

(h, k)

<u>Need to know about perfect squares </u>

<u>Need to know how to complete the square.</u>

-----------------------------------------------------------------------------------------

<u>To convert x^2-2x-5 you need to complete the square on the equation.</u>

Complete the Square x^2 - 2x -5

x^2 - 2x -5

(x^2 - 2x) -5

Divide -2 by 2 and then square it.

\frac{-2}{2} = -1

-1^2 = 1

Add the one to the parentheses and subtract the one from the 5

(x^2 - 2x +1) -5 -1

Square  (x^2 - 2x +1)

(x-1)^2

Now we have

(x - 1)^2 -5 -1

<u>Next add</u> -5 - 1 = -6

(x - 1)^2 - 6

Our quadratic is in vertex form now.

Vertex form = a(x -h)^2 + k

our equation =  (x - 1)^2 - 6

Vertex = (1, -6)

5 0
4 years ago
What statements are correct? Check all that apply. The conditional probability formula is P(x l n m PO) The conditional probabil
Monica [59]

The first , second, and fourth options if you are on edge.

4 0
4 years ago
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

7 0
4 years ago
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