Answer:
1. $82,500
2. 169 : 110
Step-by-step explanation:
The computation is shown below:
Given that
1. Ratio between two computers is 3:2
And the first computer cost is $55,000
Let us assume the price of the second computer be x.
As we know that
Product of extremes = Product of mean.
2 : 3 :: 55000 : x .
Now cross mutiplication is to be done
2x = $55,000 × 3
x = $1,650,000 ÷ 2
= $82,500
2. Now if the price of the 2nd computer rised by $2,000
So the new cost would be
= $82,500 + $2,000
= $84,500
Now the ratio would be
= $55,000 : $84,500
= 169: 110
First change the 0.05 to a fraction.
0.05 = 1/20
Then you have the equation:
10/20 = 0.5
I think the correct answer would be : p = -n+4m/L
I hope this helps !
Answer:
Part a) variable x (the number of adult tickets sold) and variable y (the number of child tickets sold)
Part b) 
Part c) The number of adult tickets sold was 86
Step-by-step explanation:
Part a) Name a variable for the number of adult tickets sold and name a variable for the number of child tickets sold
Let
x -----> the number of adult tickets sold
y -----> the number of child tickets sold
Part b) Write an equation in two variables to model the problem
we know that
-----> equation A
-----> equation B
substitute equation B in equation A and solve for x


Part c) Using your equation in Part B, solve the problem and answer the question "how many adult tickets did Anne sell?" i
we have

Solve for x
Subtract 416 both sides



therefore
The number of adult tickets sold was 86