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xz_007 [3.2K]
3 years ago
15

-

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

if you have a bad credit score it can increase your debt ratio

Step-by-step explanation:

You might be interested in
The ratio of two computers is 3:2.
serious [3.7K]

Answer:

1. $82,500

2. 169 : 110

Step-by-step explanation:

The computation is shown below:

Given that

1. Ratio between two computers is 3:2

And the first computer cost is $55,000

Let us assume the price of the second computer be x.

As we know that

Product of extremes = Product of mean.

2 : 3 :: 55000 : x .

Now cross mutiplication is to be done

2x = $55,000 × 3

x = $1,650,000 ÷ 2

= $82,500

2. Now if the price of the 2nd computer rised by $2,000

So the new cost would be

= $82,500 + $2,000

= $84,500

Now the ratio would be

= $55,000 :  $84,500

= 169: 110

8 0
3 years ago
How could you rewrite 0.05 × 10 = 0.5 as a division equation ? explain how you know
Artist 52 [7]
First change the 0.05 to a fraction.
0.05 = 1/20
Then you have the equation:
10/20 = 0.5
5 0
3 years ago
Read 2 more answers
Pls help me. its on khan academy​
ehidna [41]
i would think it’s 6
8 0
3 years ago
Read 2 more answers
L=4m\n+p solve for p
Anastasy [175]
I think the correct answer would be : p = -n+4m/L
I hope this helps !
7 0
3 years ago
At a movie theater, admission tickets cost $10 for adults and $8 for children. On Saturday, Anne Teak collected a total of $1276
kow [346]

Answer:

Part a) variable x (the number of adult tickets sold) and variable y (the number of child tickets sold)

Part b) 10x+8y=1,276

Part c) The number of adult tickets sold was 86

Step-by-step explanation:

Part a) Name a variable for the number of adult tickets sold and name a variable for the number of child tickets sold

Let

x -----> the number of adult tickets sold

y -----> the number of child tickets sold

Part b) Write an equation in two variables to model the problem

we know that

10x+8y=1,276 -----> equation A

y=52  -----> equation B

substitute equation B in equation A and solve for x

10x+8(52)=1,276

10x+416=1,276

Part c) Using your equation in Part B, solve the problem and answer the question "how many adult tickets did Anne sell?" i

we have

10x+416=1,276

Solve for x

Subtract 416 both sides

10x=1,276-416

10x=860

x=86

therefore

The number of adult tickets sold was 86

7 0
3 years ago
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