Can someone help 30 points!

Mathematics

1 answer:

irina1246 [14]3 years ago

3 0

We cannot solve for a numerical value of p, but rather set the equation equal to p.

w = 4/(p+2)

(Multiply both sides by the denominator)

w(p+2) = 4

(divide both sides by w)

p+2 = 4/w

(Subtract 2 from both sides) (also 2/1)

p = (4-2)/w

p = 2/w

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DO NOT OVERLOOK THIS!!!!!!!!

zmey [24]

<h2>Answer:</h2>

<u>Area</u> = 2(1/2 × 5 × 5) + 20 × 10

= 2 × 12.5 + 200

= 25 + 200

= 225ft².

3 0

3 years ago

J. J. Redick is an excellent free throw shooter and makes 90% of his free throws (i.e., he has a 90% chance of making a single f

irakobra [83]

Answer:

59.049%

Step-by-step explanation:

J. J. Redick is an excellent free throw shooter and makes 90% of his free throws

P(making one free throw) =90%

Therefore:

$P($making 5 consecutive free throws)=P(making 1st) X P(making 2nd) X P(making 3rd)X P(making 4th) X P(making 5th)\\\\=90\%X90\%X90\%X90\%X90\%\\\\=0.9X0.9X0.9X0.9X0.9\\\\=0.59049\\\\=59.049\%$

7 0

3 years ago

Please write the answer

Travka [436]

$\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\ \\ \longrightarrow \sf \: 27 - 15 \\ \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}$