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sammy [17]
4 years ago
14

I need help with my homework points is 13​

Mathematics
1 answer:
sladkih [1.3K]4 years ago
3 0

Answer: see below

<u>Step-by-step explanation:</u>

x + 2:

a number x plus 2

the sum of a number x and 2

x - 2:

a number x minus 2

the difference of a number x and 2

2x:

two times a number x

twice a number x

x ÷ 2:

a number x divided by 2

the quotient of a number x and 2

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An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.
strojnjashka [21]

Answer:

1. The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

2. The point estimate for the true difference between the population means is of -1872.

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of Normal Variables:

When two normal variables are subtracted, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 212 brakes using Compound 1 yields an average brake life of 47,895 miles. The population standard deviation for Compound 1 is 1590 miles.

This means that \mu_1 = 47895, \sigma_1 = 1590, n = 212, s_1 = \frac{1590}{\sqrt{212}} = 109.2

A sample of 180 brakes using Compound 2 yields an average brake life of 49,767 miles. The population standard deviation for Compound 2 is 4152 miles.

This means that \mu_2 = 49767, \sigma_2 = 4152, n = 180, s_2 = \frac{4152}{\sqrt{180}} = 309.47

True difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2.

This is the distribution 1 - 2. So

\mu = \mu_1 - \mu_2 = 47895 - 49767 = -1872

This is also the point estimate for the true difference between the population means, which is question 2.

s = \sqrt{s_1^2+s_2^2} = \sqrt{109.2^2+309.47^2} = 328.17

90% confidence interval

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs = 1.645*328.17 = 539.84

The lower end of the interval is the sample mean subtracted by M. So it is -1872 - 539.84 = -2411.84

The upper end of the interval is the sample mean added to M. So it is -1872 + 539.84 = -1332.16.

The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

5 0
4 years ago
Original price:<br> Discount:<br> 30%<br> Sale price:<br> $206.50
REY [17]
The answer is $295. I also added my work below!

4 0
3 years ago
HHHHHEEEEELLLLLPPPPP PLEASEEE!!!!
alukav5142 [94]

Answer:

15 times per seconds

Step-by-step explanation:

basta 15 times per seconds

4 0
3 years ago
What is the equation of the graphed line written in standard form
weqwewe [10]
Ax+by=c


First you'll find the equation of the graphed line in slope-intercept form, y = mx+b, and then from there we'll convert it into standard form, ax+by = c.
5 0
3 years ago
The price of gas was $1.80 in September then $2.07 in October. Find the percent of change from
Aleksandr [31]
The percent increase from $1.80 to $2.07 is 15%.

2.07 / 1.80 = 1.15 - 1 = 15% increase.

If you were trying to find how much $1.80 of $2.07 was in percentage, then here you go:

1.80 * 100 (out of 100%) = 180
180 / 2.07 = 86.95
86.95%
8 0
4 years ago
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