Grade In Favor Opposed Undecided Total
9 4 2 8 14
10 7 11 8 26
11 14 15 9 38
12 11 5 10 26
Total 36 33 35 104
Above is a partial sum chart that will help us in our quest.
P(Grade 9 | opposed)
The probability of Grade 9, given opposed, is the portion of opposed students that are in grade 9.
Total number opposed: 33
Number opposed in Grade 9: 2
P(Grade 9 | opposed) = 2 / 33 = 0.06
P(opposed | Grade 9)
Total Number Grade 9: 14
Number opposed in Grade 9: 2
P(opposed | Grade 9) = 2 / 14 = 0.14
Answer:
35 is 2 standard deviations BELOW the mean of 43
51 is 2 standard deviations ABOVE the mean of 43
find z - score for + 2 S.D. then subtract the z-score for - 2 S.D.
This is the percentage ( in decimal form) of 200 members between the ages of 35 and 51 Can you finish?
Answer:
the probability is 1/5 or 25%
Step-by-step explanation:
since the possible answers are 1,2,3,4, or 5, and only one is chosen, there is a 1/5 chance of getting each number.
