Question

What’s 8x squared + 4 in vertex form

Answer 1

expression  8x squared + 4  or , $8x^2+4$ in the vertex form is  $8(x+0)^2+4$ .

Step-by-step explanation:

Here we have , to convert expression  8x squared + 4  or , $8x^2+4$ in the vertex form . Let's find out:

Let  $y=8x^2+4$ ,

⇒   $y=8x^2+0(x)+4$

Comparing this equation with $y = ax^2+bx+c$ we get ;

$a=8\\b=0\\c=4$

Now , We know that  the vertex form of a parabola is ;

⇒ $a(x+d)^2+e$     ............(1)

Substitute the values of  a  and  b  into the formula $d =\frac{b}{2a}$

⇒ $d=\frac{0}{2(8)} =0$

Now , Value of e is ;

⇒ $e= c- \frac{b^2}{4a}$

⇒ $e=4$

Putting value of a, d ,e in equation (1) we get ;

⇒ $a(x+d)^2+e$  

⇒ $8(x+0)^2+4$

Therefore ,  expression  8x squared + 4  or , $8x^2+4$ in the vertex form is  $8(x+0)^2+4$ .