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Yuliya22 [10]
3 years ago
9

A polynomial function can be written as (x + 2)(x + 3)(x − 5). What are the x-intercepts of the graph of this function? (1 point

) (2, 0), (3, 0), (−5, 0) (−2, 0), (−3, 0), (5, 0) (2, 0), (3, 0), (5, 0) (−2, 0), (−3, 0), (−5, 0)
Mathematics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer:

<h2>(-2, 0), (-3, 0) and (5, 0)</h2>

Step-by-step explanation:

x-intercepts are for

(x + 2)(x + 3)(x - 5) = 0

The product is equal to 0 if one of the factors is equal to 0.

Therefore

x + 2 = 0 or x + 3 = 0 or x - 5 = 9

x + 2 = 0     <em>subtract 2 from both sides</em>

<em>x = -2</em>

x + 3 = 0<em>        subtract 3 from both sides</em>

<em>x = -3</em>

x - 5 = 0              <em>add 5 to both sides</em>

<em>x = 5</em>

Marizza181 [45]3 years ago
6 0

Answer:

(-2, 0), (-3, 0), and (5, 0)

Step-by-step explanation:

The x-intercept is found when <em>y = 0</em>.

So, we have to find x when <em>(x + 2)(x + 3)(x - 5) = 0</em>

We can do that by pulling apart all parts, because if one part = 0, the whole thing will have to be too (multiplication property of identity).

1. When x + 2 = 0, x = -2

2. When x + 3 = 0, x = -3

3. When x - 5 = 0, x = 5

That gives us (-2, 0), (-3, 0), and (5, 0)

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