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3 years ago

4x-3y=1 -8x+6y=-2 elimination method

Mathematics

1 answer:

Alex787 [66]3 years ago

4 0

(4x-3y=1)×2

8x-6y=2

8x-6y+(-8x+6y)=2+(-2)

8x-8x=0

0=0

apply it ,

4×0-3y=1

-3y=1

y=-1/3

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LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)

klasskru [66]

$\huge \bf༆ Answer ༄$

Let's solve ~

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Hence, the correct choice is D

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2 years ago

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Sanjay read 56 pages of his book this weekend.This is 35% of the pages in the book.How many pages are in Sanjays book?

Maurinko [17]

1. 56 : 35 = 1.6
2. 1.6* 100 = 160
3. The answer is 160

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3 years ago

A football player is running the length of a 100 yard long football field. For the first part of the field, he runs at a rate of

notka56 [123]

Answer:

$\frac{2}{5}$ th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = $\frac{x}{2}$ seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = $\frac{Distance}{Speed}$

= $\frac{100-x}{4}$ seconds

Now total time taken by the player can be represented by the equation

$\frac{x}{2}+\frac{100-x}{4}=40$

Now we can solve this equation for the value of x.

$\frac{2x+100-x}{4}=40$

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

= $\frac{40}{100}$

= $\frac{2}{5}$ or 40%

Therefore, $\frac{2}{5}$ th part of the field was covered in second sprint.

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3 years ago

Area of of a parrolalogram of a base of 30 feet and a height of 20 feet

Basile [38]

Answer:

600

Step-by-step explanation:

Multiply 30 x 20

7 0

2 years ago

Please answer the question!

Airida [17]

ANSWER

$Area = 2\sqrt{3} \: {cm}^{2}$

EXPLANATION

We need to use the Pythagoras Theorem to find the height of the triangle.

${a}^{2} + {b}^{2} = {c}^{2}$

$({2 \sqrt{3}) }^{2} + {b}^{2} = {4}^{2}$

$12 + {b}^{2} = 16$

${b}^{2} = 16 - 12$

${b}^{2} = 4$

Take positive square root to get;

$b = \sqrt{4} = 2$

Area =½bh

$Area = \frac{1}{2} \times 2\sqrt{3} \times 2$

$Area = 2\sqrt{3} \: {cm}^{2}$

7 0

3 years ago