Question

Will mark Brainlest hellpppp​

Answer 1

$h(-3) - h( - 2) = - \frac{5}{ 8}$

Step-by-step explanation:

$\boxed{h(x) = \frac{2 {x}^{2} - x + 1}{3x - 2}}$

$h(2) = \frac{2 {(2)}^{2} - (2) + 1}{3(2) - 2}$

$h(2) = \frac{2 {(4)} - 2 + 1}{6 - 2}$

$h(2) = \frac{ 8 - 1}{4}$

$h(2) = \frac{7}{4}$

$h( - 3) = \frac{2 {( - 3)}^{2} - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) = \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) = \frac{18 + 4}{ - 11} \\ h( - 3) = \frac{22}{ - 11} \\ h(-3) = -2$

$h( - 2) = \frac{2 {( - 2)}^{2} - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) = \frac{2 (4) + 2+ 1}{- 6 - 2} \\ h( - 2) = \frac{8 + 3}{- 8} \\ h( - 2) = \frac{11}{- 8}$

$h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}$