You randomly draw two cards from a standard deck of playing cards without replacement.what is the probability that both of the c
2 answers:
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First, when multiplying percents, you need to convert them to decimals. You convert percents to decimals by multiplying by 100 or moving the decimal two places to the left. Once you convert them to full decimals, you multiply the decimal by the number that you are getting the percentage from
61% of 180⇒.61×180=<u>109.8 </u>
5.1% of 81?⇒.051×81=<u>4.131
</u>
of 36?⇒16.5×36⇒.165×36=<u>5.94
</u>81% of 241⇒.81×241=<u>195.21</u>
76% of 600⇒.76×600=<u>456</u>
88% of 680⇒.88×680=<u>598.4</u>
37% of 481⇒.37×481=<u>177.97</u>
19.1% of 380⇒.191×380=<u>72.58</u>
41% of 321⇒.41×321=<u>131.61</u>
33% of 331⇒.33×331=<u>109.23</u>
61% of 180⇒.61×180=<u>109.8 </u>
5.1% of 81?⇒.051×81=<u>4.131
</u>
</u>81% of 241⇒.81×241=<u>195.21</u>
76% of 600⇒.76×600=<u>456</u>
88% of 680⇒.88×680=<u>598.4</u>
37% of 481⇒.37×481=<u>177.97</u>
19.1% of 380⇒.191×380=<u>72.58</u>
41% of 321⇒.41×321=<u>131.61</u>
33% of 331⇒.33×331=<u>109.23</u>