Sin(2θ)+sin(<span>θ)=0
use double angle formula: sin(2</span>θ)=2sin(θ)cos(<span>θ).
=>
2sin(</span>θ)cos(θ)+sin(<span>θ)=0
factor out sin(</span><span>θ)
sin(</span>θ)(2cos(<span>θ)+1)=0
by the zero product property,
sin(</span>θ)=0 ...........(a) or
(2cos(<span>θ)+1)=0.....(b)
Solution to (a): </span>θ=k(π<span>)
solution to (b): </span>θ=(2k+1)(π)+/-(π<span>)/3
for k=integer
For [0,2</span>π<span>), this translates to:
{0, 2</span>π/3,π,4π/3}
Answer:
D because even though the flat fee is 150 paying 5$ a hour it will cost less
Answer:
(x) = 
Step-by-step explanation:
let y = f(x) , then rearrange making x the subject
y = 6x + 7 ( subtract 7 from both sides )
y - 7 = 6x ( divide both sides by 6 )
= x
Change y back into terms of x with x = (x) , then
(x) =
Dividing x5^5 / x5^5 is 1
