Your final answer for this question is -3(y-2)/2. Hope this helps.
- Length (l) = 45 m
- Breadth (b) = 30 m
- We know, perimeter of a rectangle = 2(length + breadth)
- Therefore, perimeter of the rectangle
- = 2(I + b)
- = 2(45 + 30) m
- = 2 × 75 m
- = 150 m
- So, the distance travelled by Rubina
- = 4 × 150 m
- = 600 m
<u>Answer:</u>
<em><u>The </u></em><em><u>distance </u></em><em><u>travelled</u></em><em><u> </u></em><em><u>by </u></em><em><u>Rubina </u></em><em><u>is </u></em><em><u>6</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>m.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
Yes. Distributive property
Step-by-step explanation:
3(a + b)
Opening bracket
= 3(a) + 3(b)
= 3a + 3b
Answer:
wet by solar..................
Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)