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3 years ago

A card is drawn from a standard 52-card deck. What is the probability that the card is a red 8, given that the card is an 8?

Mathematics

2 answers:

crimeas [40]3 years ago

8 0

<span>probability that the card is a red 8
=
2 out of 52 or 1 out of 26

hope it helps</span>

Anika [276]3 years ago

7 0

there are 2 red 8's in a deck so it would be 2/52 which can be reduced to a

1/26 probability

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

What is negative 5 and 3/4 as a fraction

Alinara [238K]

Answer:

-23/4

Step-by-step explanation:

$-5\frac{3}{5}$

$-\frac{5x4+3}{4}$

$-\frac{20+3}{4}$

$-\frac{23}{4}$

3 0

3 years ago

7th grade Ms. Takemoto wants to raise her math grade to a 95 to improve her chances of winning a math scholarship. Her math aver

malfutka [58]

No, 15% of 81 is 12.5 and 81+12.5 is only 93.5 and she needs at least a 95

8 0

3 years ago

The measure of an angle is 78°. What is the measure of a complementary angle?

ki77a [65]

First you need to know the definition of a complementary angle. That means that two angles add up to 90 degrees, or a right angle.

To find an angle complementary to a 78 degree angle, you need to subtract 78 from 90.

90 - 78 = 12

6 0

3 years ago

Read 2 more answers

Once again co sines . Please help me and include explanation with a clear answer

vladimir1956 [14]

Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)

a = 17, b = 8, c = 16

8^2 = 17^2 + 16^2 - 2*17*16* cos(B)

64 = 289 + 256 - 544 * cos(B)

544*cos(B) = 289 + 256 - 64

544 * cos(B) = 481

cos (B) = 481/544

B = arccos(481/544)

B = 27.8 degrees

8 0

3 years ago