Q = 6 and p = 5
It’s a parallelogram so the side opposite are the same.
6 = q - 3
Subtract 3 and add it to 6 and you get 9
9=q
Answer:
<h2>2</h2>
Step-by-step explanation:
Given g(x)=5x-4 and g(x)=f^{-1}(x)-3
Substituting g(x) = 5x-4 into the second equation we have;
5x-4 = f^{-1}(x)-3
f^{-1}(x) = 5x-4+3
f^{-1}(x) = 5x-1
To get f(x), let us first make y to be equal f^{-1}(x)
y = 5x-1
expressing x in terms of y to get f(x), we have;
5x = y+1
x = y/5+1/5
replacing y with x, we will have;
y = x/5 + 1/5
F(x) = x/5 + 1/5
Comparing x/5 + 1/5 with ax+b, a = 1/5 and b = 1/5
5a + 5b = 5(1/5)+ 5(1/5)
5a+5b = 1+1
5a+5b = 2
Answer:
Step-by-step explanation:
We want a line parallel to 3x − 4y = 7. Any such line will have an equation of the same form but a different constant.
If the new line is to pass through the point (-4, -2), replace x with -4 and y with -2. We obtain:
3(-4) − 4(-2) = -12 + 8 = -4. Thus, the desired new equation is 3x − 4y = -4.
This could also be written as 3x − 4y + 4 = 0. We could also solve this for y, obtaining:
3x + 4 = 4y, or y = (3/4)x + 1.
Answer:
8800
Step-by-step explanation:
<span>It means that the point lies directly on the regression line.
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