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3 years ago

Does 3 to the 2 power plus 3 to the 3 power equal 3 to the 5 power? Please Explain!

1 answer:

4 0

No because if you do the math, 3 to the power of 2 you get 9 and if you do 3 to the power of 3 you get 27. However when you do 3 to the power of 5 you get 243. Add 27 and 9 and you get 36 which is not 243.

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I don’t understand what to do

Natasha2012 [34]

Answer: 14cm

Step-by-step explanation:

The diameter of a circle is twice the radius.

Therefore, the diameter = 2*7 cm = 14cm

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2 years ago

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Problem 2.2

lana [24]

Answer:

$3.60.

Step-by-step explanation:

4.5 = x + 20% of x

4.5 = x + 0.2x

1.2x = 4.5

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2 years ago

Помогите решить, пожалуйста, с 1-8. Дам 50 баллов.

kifflom [539]

Answer:

Step-by-step explanation:

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2 years ago

Wazma bought some new pants, but the 34 inch inseam was too long. If he wants the inseam to be 3013 inches long, how much length

KiRa [710]

The length of the inseam to be removed from the pant is 3 2 / 3 inches.

<h3 /><h3>How to find the length to be removed?</h3>

The length of the pant he bought is 34 inches and it was too long.

He wants the length to be 30 1 / 3 inches long.

Therefore, the amount of length to be removed can be calculated as follows;

34 - 30 1 / 3

$30\frac{1}{3} = \frac{91}{3}$

Hence,

$34-\frac{91}{3}=\frac{102-91}{3} =\frac{11}{3}=3\frac{2}{3} inches$

Therefore, the number to be removed is 3 2 / 3 inches

learn more on length here: brainly.com/question/11427600

#SPJ1

7 0

2 years ago

Verify identity: <br><br> (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

7 0

3 years ago