Answer:
1716 ways
Step-by-step explanation:
Given that :
Number of entrants = 13
The number of ways of attaining first, second and third position :
The number of ways of attaining first ; only 1 person can be first ;
Using permutation :
nPr = n! ÷(n-r)!
13P1 = 13! ÷ 12! = 13
Second position :
We have 12 entrants left :
nPr = n! ÷(n-r)!
12P1 = 12! ÷ 11! = 12
Third position :
We have 11 entrants left :
nPr = n! ÷(n-r)!
11P1 = 11! ÷ 10! = 11
Hence, Number of ways = (13 * 12 * 11) = 1716 ways
Answer:
it is 29in
Step-by-step explanation:
If it is packed 2/5 in 1/2 minutes
1 minute =2/5*2=4/5 or 0.8 boxes/min
<span>5 + 2i–4i + 15i12
2+ square root of 6</span>
I belive the answer is 1.
This is because out of 22 ribbon there are 10 which are bue so the probability of blue ribbons is 10/22 and probability of red ribbon is 12/22. So your question was the probability of choosing a red ribbon then a blu ribbon. Because of the word "then" , this means it is simply asking you to add their probablity so after adding 10/22 with 12/22 your answer will come to 22/22 which is equal to 1.
