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juin [17]
4 years ago
13

For a given input value v, the function f outputs a value u to satisfy the following equation.

Mathematics
1 answer:
tigry1 [53]4 years ago
8 0

Answer: -4v+9

Step-by-step explanation:

u - 5 = -4(v - 1)

u - 5 = -4v + 4

+5 +5

u = -4v + 9

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Just #2 . Help !! Please :)
kirza4 [7]
180- 113 = 67

180- 67= 113

<5= 67
<2=113
8 0
3 years ago
Read 2 more answers
Evaluate z + 2+ z for x = 2, y=-3, z = -4.
Artyom0805 [142]

Answer:

-6

Step-by-step explanation:

Are you sure that z + 2+ z is correct?  x and y do not appear here.

z + 2+ z simplifies to 2z + 2, and so, if z = -4, z + 2+ z has the value

2(-4) + 2, or -6.

7 0
3 years ago
One and one tenth decimal number
Elden [556K]
Hi there!

One and one tenth looks hard but that would be because it's in word form.
In standard, or decimal form, this would be 1.1.
The first 1 represents the whole number and the second 1 represents the tenths.

Hope this helps! Let me know if you need anymore help! :)
3 0
3 years ago
Read 2 more answers
Kendra found this relationship between the quantities in the table.
slava [35]

Answer:

Kendra should have multiplied the x-values by 75 to get the y-values

Step-by-step explanation:

Given

Table

X|| Y

1 || 75

2 || 150

3 || 225

4 || 300

5 || 375

Given that Kendra multiply x by 7.5 to get y

The relationship of x and y can be calculated as thus;

y = rx

Where y and x are the values at the y and x column respectively and r is the constant of proportionality

When y = 75, x = 1.

Plug in these values in the above formula

y = rx becomes

75 = r * 1

75 = r

r = 75

When y = 150, x = 2

150 = r * 2

Multiply both sides by ½

150 * ½ = r * 2 * ½

75 = r

r = 75

When y = 225, x = 3

225 = r * 3

Multiply both sides by ⅓

225 * ⅓ = r * 3 * ⅓

75 = r

r = 75

Notice that r remains 75 and the difference between y values is 75

If you apply these formula on when y = 300 or 375 and when x = 4 or 5, the constant of proportionality will remain The value of 75.

Hence, Kendra mistake is that; Kendra should have multiplied the x-values by 75 to get the y-values

6 0
3 years ago
Read 2 more answers
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
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