Answer:
when x is 2, y is -4
None of the objectives is right
Answer:
P= 30 cm
Step-by-step explanation:
Formula for Rectangle Perimeter P=2(l+w)
P=2(10+5)
P=2(15)
P=30
Answer: c. elm
Step-by-step explanation:
Given : The circumference of the oak tree= 0.539 meters
=
[∵ 1 m = 100 cm] (1)
The circumference of the ash tree= 0.509 yards
[∵ 1 yard = 3 feet]
[∵ 1 foot = 30.48 cm]
(2)
The circumference of the elm tree = 6281.70 millimeters
(3)
The circumference of the poplar tree = 0.000385 miles
[∵ 1 mile = 5280 feet]
[∵ 1 foot = 30.48 cm]
(4)
From (1) , (2) , (3 ) and (4) it is clear that
46.54< 53.9 < 61.96 < 628.17
Hence, the elm tree has the greatest circumference.
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
The answer is “A” as when the width is multiplied by the row foot, you get approximately 3 times the amount.
I hope that’s correct and I hope I could help :)
