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salantis [7]
3 years ago
15

What is the value of the expression 2 to the third power plus 3 over 5 times 5 over 9 minus 4 plus 3.?

Mathematics
1 answer:
n200080 [17]3 years ago
5 0
Suffdfudududududhrhehrhdudh
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On a map, in. Represents 20 mi. Two cities are 3 1/2 in. Apart on the map
Bad White [126]
The right answer is C) 70 miles.
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4 years ago
Which shows one way to determine the factors of x3 11x2 – 3x – 33 by grouping? x2(x 11) 3(x – 11) x2(x – 11) – 3(x – 11) x2(x 11
Aloiza [94]

The one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The steps involved in the factorization are;

1. For each pair of parentheses, we create a common factor.

2. We use x2 as a common factor for the first parenthesis.

3. We use common factor 3 for the second parenthesis.

x^3  + 11x^2 - 3x -33 \\\\ x^2(x+11)-3(x+11)_

We will find the final solution as x^2(x+11)-3(x+11)_.

Hence the one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

To learn more about the factorization refer to the link;

brainly.com/question/24182713

3 0
2 years ago
A store has a sale on paper cups, 200 cups for $15.00. During the sale, what is the unit price per cup?
Anna35 [415]

Answer:

it's either 200:15 or 20:15 or 15:20

Step-by-step explanation:

6 0
4 years ago
Sophia's school has 23 classrooms. Each classroom has 10 tables. How many tables are there in the school? ​
amid [387]
If there is 23 classrooms and each has 10 then you would have to times 23 by 10 - 23x10=230
4 0
3 years ago
Read 2 more answers
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
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