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Dovator [93]
3 years ago
9

If 14 g of a radioactive substance are present initially and 7 yr later only 7 g​ remain, how much of the substance will be pres

ent after 17 ​yr?
Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

2.60 gr

Step-by-step explanation:

We need to consider the function P(t) = P_oe^{kt} where Po is the initial substance k is the rate of decay and t is the time

We know that P_o = 14 and at the 7 th year P(t) is 7

This means

7 = 14e^{7k}

We solve for k

\frac{7}{14} = e^{7k}\\\\\ln (\frac{7}{14}) = 7k\\\\k = \frac{\ln (7/14)}{7} = -0.099\\\\Then \ P(t) = 14e^{-0.099t}\\\\Now \  we \ take \ t = 17\\\\P(17) = 14e^{(-0.099)(17)} = 2.60

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3 years ago
Gene is playing a game with a bag of marbles. 3 of the marbles are blue, 4 are green, and 7 are yellow. See below for awarded pr
jek_recluse [69]

Answer:

<h2><em>$23.5</em></h2>

Step-by-step explanation:

Gene is playing a game with a bag of marbles. If 3 of the marbles are blue, 4 are green, and 7 are yellow and awarded prices for the marbles are $2 green $0.5 yellow $4 blue, the expected payout for Gens game is expressed as shown;

If a blue marble costs $4, 3 blue marbles will cost 3*$4 = $12

If a green marble costs $2, 4 green marbles will cost 4*$2 = $8.0

If a yellow marble costs $0.5, 7 yellow marbles will cost 7*$0.5 = $3.5

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3 years ago
I need the answer ASAP Ill give five stars to whoever answers it.
zmey [24]
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4 0
3 years ago
The sum of two numbers is 90. the larger number is 6 less than twice the smaller. find the numbers.
lana [24]

Answer:

32 and 58

Step-by-step explanation:

Let's set up equations.

The sum of two numbers (x and y) is 90: x + y = 90

The larger number (y) is 6 less than twice the smaller number (x): y = 2x - 6

We have our system of equations:

x + y = 90

y = 2x - 6

Let's use substitution.

Substitute y = 2x - 6 into the first equation.

x + y = 90

x + (2x - 6) = 90

Combine like terms.

x + 2x - 6 = 90

3x - 6 = 90

Add 6 to both sides to isolate x.

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Divide both sides by 3 to further isolate x.

x = 32

Now that we know x, let's find y.

Plug in x = 32 into one of our original equations.

y = 2x - 6

y = 2(32) - 6

Multiply.

y = 64 - 6

y = 58

Now we have x = 32, y = 58.

Check your answer by plugging these values into one of our original equations.

x + y = 90

32 + 58 = 90

Add.

90 = 90

Your solution is correct.

Hope this helps!

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3 years ago
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Answer:

1)

a) 4^1

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