Answer:
270 cm^2
Step-by-step explanation:
This is quite easy.
There is formula for it, the formula is bh/2
b= is the base or side that the triangle's altitude or height is perpendicular to.
h= is the height of the triangle or the altitude of the triangle.
I can always like to thing that a triangle is like half of a rectangle because the area for a rectangle is bh, but in a triangle it is half the bh.
b= 30
h=18
Now substitute the values in the formula
30(18)/2
30 times 18 = 540
divide the product by 2
540/2 = 270
If the line segment point is D(-5, 10) and E(a,b) and the midpoint of the segment is F(13, -2) that mean
DE= 2*DF
You can directly find the distance of AC
Xdf= Xf-Xd= 13 - (-5)= 18
Ydf= Yf - Yd= -2 - 10= -12
Then add the distance of AB( which is 2*AC) to point D
Xe= a = Xd + 2*Xdf
a= -5 +2*18= 31
Ye= b = Yd + 2Yf
b= 10+ 2*-12= -14
<span>absolute difference between a and b:
|b-a|= </span>|-14-31|= 45
