1. Reduction: 1/2
2. 200 millimeters
3. Glide Reflection
What is GH and DE? is there a picture lol
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
The radius is 2 and area = r^2*pi so 4*pi gives you 12.56 so the exact answer would be 12.56 and the answer with pi would be 4 times 3.14!
Answer:
6 meters by 9 meters
Step-by-step explanation:
<u><em>Step 1: Formula for perimeter of rectangle</em></u>
Rectangle's perimeter = 2 (length) + 2 (width)
Rectangle's perimeter = 2 (length + width)
<u><em>Step 2: Find the length and width in terms of x</em></u>
Width = x
Length = 1.5 times width
Length = 1.5x
<u><em>Step 3: Find x</em></u>
Perimeter = 2(length + width)
30 = 2 (1.5x + x)
30/2 = 2.5x
15/2.5 = x
x = 6
<u><em>Step 4: Find the length and width</em></u>
Width = x = 6 meters
Length = 1.5x = 1.5(6) = 9 meters
Therefore, the dimensions of the room are 6 meters and 9 meters.