Answer:
(2)
Step-by-step explanation:
Our logarithmic expression is:
.
Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

Also, we can write square roots as powers of one-half, so √e =
. There's another log property that:
. We can apply that here for both the √e and the y³:

Finally, note that ln(e) is just 1, so we have:

The answer is thus (2).
<em>~ an aesthetics lover</em>
Answer:
are there answer choices?
Step-by-step explanation:
Answer:
11/15 OR 0.73
Step-by-step explanation:
2/5 ---> 6/15
1/3 ---> 5/15
6/15 + 5/15 = 11/15
OR
2/5 ---> 0.4
1/3 ---> 0.33
0.4 + 0.33 = 0.73
<h2>
Answer:</h2>
The probability that the customer did not try on the t- shirt is:
0.2432
<h2>
Step-by-step explanation:</h2>
It is given that the probability that a customer tries a t-shirt is: 0.40
After he will try
The probability that he will buy the t-shirt is: 0.70
The probability that he will not try t-shirt is: 1-0.40=0.60
If he will not try
then the probability of buying a t-shirt is: 0.15
This means that the total probability of Buying a t-shirt is:
0.40×0.70+0.60×0.15
= 0.37
It is given that the customer bought a t-shirt, we need to find the probability that he did not try the t-shirt:
The probability is given by:

Answer:
85.99% of airline passengers incur this fee.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean 46 pounds and standard deviation 3.7 pounds.
This means that 
Most airlines charge a fee for baggage that weigh in excess of 50 pounds. Determine what percent of airline passengers incur this fee.
As a proportion, this is 1 subtracted by the pvalue of Z when X = 50. So



has a pvalue of 0.8599
0.8599*100% = 85.99%
85.99% of airline passengers incur this fee.