Hi i’m answering on here so i can ask someone something through the messages bc i haven’t answered enough questions
Answer:
The radius of the circle is 
Step-by-step explanation:
we know that
The circumference of a circle is equal to

In this problem we have


substitute and solve for r


B=1/2
9/16=1/2b(3/4)
Divide both sides by 3/4
1/4=1\2b
Multiply both sides by 2
The domain and range of the composition of f of g is not necessarily equal to the domain and range of g since the function f . This will only be true if the domain and range of the function f is (negative infinity, infinity).<span />