Answer:
This question is incomplete
Explanation:
This question is incomplete but the completed question can be seen in the document attached.
There are three main subatomic particles namely electrons, protons and neutrons. However, the question only discusses two of them; electrons (negatively charged) and protons (positively charged).
A. Found in all matter
Answer: They are <u>both</u> found in all matter since all matter are made up of atoms and all atoms have both protons and electrons (and even neutrons).
B. Negative charge
Answer: The subatomic particle with negative charge (as discovered by R.A Millikan) is the <u>electron</u>
C. Exists in the nucleus
The subatomic particles found in the nucleus are the <u>protons</u> and neutrons.
D. Attract opposite charges
They <u>both</u> (protons and electrons) attract opposite charges because they are of opposite charges and generally unlike charges attract.
E. Moves at extreme speed
Of the two subatomic particles mentioned, <u>electrons</u> move faster than protons because of there lighter mass when compared to the protons. However, the fastest subatomic particle is the neutrino.
F. Bound by strong force
The <u>protons</u> are bound by strong nuclear force which binds them to the nucleus of the atom.
This is mutualism because both species benefit
Answer:
- The blood group of the father must be B.
- The genotype of blood group would be
. - The Rh factor of the father can either be positive or negative.
- Thus, the genotype of Rh factor of father would be either Rr or rr.
Rh factor:
The phenotype of the mother Rh factor is positive. Thus, she can have Rr or RR as her genotype as positive is a dominant trait.
If the genotype of the mother is RR then all the offspring would be positive for Rh factor. However, one of the offspring is Rh negative, that means the mother must be heterozygous that is, Rr.
The genotype of the father can either be Rr or rr in order to produce offspring with positive as well as negative Rh.
Blood group:
The blood group of the mother is A. Thus, the genotype can either be 
or 
.
However, the blood groups of the children are O+ and B+.
Thus, the genotype of the mother must be heterozygous that is .
The blood group of the father must be B with genotype in order to produce offspring with blood group O and B.
Answer:
The correct answer will be option-A.
Explanation:
Lac operon is a set of genes arranged sequentially for lactose metabolism in E.coli. The lac operon gets activated in the presence of lactose as the lac operon consists of three enzyme coding genes called lacZ which codes for the β-galactosidase enzyme, lacY which codes for lactose permease, lacA which codes for acetyltransferase along with a regulatory gene called lacI which codes for repressor proteins.
The repressor proteins bind to the operator and control the transcription. When it binds to operator its huts off the transcription. If a mutation occurs in the laci gene then the protein will lose the machinery which will turn off the activity of enzymes and will lead to the constitutive expression of the genes irrespective of the inducer present or not.
Thus, option-A is the correct answer.
