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otez555 [7]
4 years ago
6

A line that includes the points (7,u) and (6,6) has a slope of -8. What is the value of u?

Mathematics
2 answers:
Zielflug [23.3K]4 years ago
8 0

Answer:

(6-u)/(6-7)= (6-u)/-1= 8

6 - u = -8

-u = -14

u = 14

Tju [1.3M]4 years ago
3 0

Answer:u = - 2

Step-by-step explanation:

Slope = change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

From the information given,

Slope = - 8

y2 = 6

y1 = u

x2 = 6

x1 = 7

Therefore,

- 8 = (6 - u)/(6 - 7)

- 8 = (6 - u)/ - 1

6 - u = 8

u = 6 - 8 = - 2

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Answer:

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Step-by-step explanation:

Take the total cost and divide by the number of boxes to get the unit cost

4.98 / 8

.6225 per box

It states to round to the nearest cent

.62 cents per box

7 0
3 years ago
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Select all the situations that describe adding or subtracting opposites to make zero.
jeka94
It would be option number 3 and option number 4
4 0
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Assume the reserve requirement is 10%. First National Bank receives a deposit of $5,400. If there is no slippage, how much could
d1i1m1o1n [39]

Given:


Reserve requirement = 10%
Deposit = $5400

Find:

money the supply could expand = ?


Solution:

Money Supply = Monetary Base × Money Multiplier

Before we determine the money supply, the money multiplier must already be determined. Therefore:
$5400 (0.10) = $540

In this case, adding the two will give us the money supply
$5400 + $540 = $5940

 

Nevertheless, not all money is lent out or spent. Kept money reduces the money supply.

The restrain to the growth of the money supply when deposits expand are identified by 2 factors:

1.       The amount above (excess reserves) what they are required to hold are being kept.

2.       Their income rises as the public has the penchant to hold more cash as their income.

8 0
3 years ago
The partial fraction decomposition of 9 x 11 6 x 2 23 x 21 can be written in the form of f ( x ) 2 x 3 g ( x ) 3 x 7 , where
svlad2 [7]

Answer:

f(x) = -1

g(x) =6

\frac{-1}{2x + 3} + \frac{6}{3x + 7}

Step-by-step explanation:

The question is unreadable, however the real polynomial is:

The polynomial fraction is:

P = \frac{9x + 11}{6x^2 + 23x + 21}

And the decomposition is:

\frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

The solution is as follows:

P = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

Substitute the expression for P

\frac{9x + 11}{6x^2 + 23x + 21} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

Expand the numerator of the polynomial

\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

Take LCM

\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)*(3x + 7) + g(x)*(2x + 3)}{(2x + 3)(x + 7)}

Cancel out both denominators

9x + 11} = f(x)*(3x + 7) + g(x)*(2x + 3)

Represent f(x) as A and g(x) as B

9x + 11} = A*(3x + 7) + B*(2x + 3)

Open bracket

9x + 11} = 3Ax + 7A + 2Bx + 3B

9x + 11} = 3Ax + 2Bx+ 7A  + 3B

9x + 11} = (3A + 2B)x+ 7A  + 3B

By comparison:

3A + 2B = 9 ---- (1)

7A  + 3B =11 ---- (2)

Make B the subject in (1)

B = \frac{9 - 3A}{2}

Substitute B = \frac{9 - 3A}{2} in (2)

7A + 3(\frac{9 - 3A}{2}) = 11

Multiply through by 2

2*7A +2* 3(\frac{9 - 3A}{2}) = 11*2

14A + 3(9 - 3A) = 22

14A + 27 - 9A = 22

Collect Like Terms

14A - 9A = 22-27

5A = -5

A = \frac{-5}{5}

A = -1

Recall that:

B = \frac{9 - 3A}{2}

B = \frac{9 - 3 * -1}{2}

B = \frac{9 + 3}{2}

B = \frac{12}{2}

B = 6

A = -1 and B = 6

3A + 2B = 9 ---- (1)

7A  + 3B =11 ---- (2)

So:

f(x) = A

f(x) = -1

g(x) =B

g(x) =6

And the decomposition is:

\frac{-1}{2x + 3} + \frac{6}{3x + 7}

6 0
2 years ago
Write an equation of the parabola in intercept form that passes through (−18, 72) with x-intercepts of −16 and −2.
seraphim [82]

y = a(x + 16)(x + 2)

72 = a(-18 + 16)(-18 + 2)

72 = a(-2)(-16)

72 = a(32)

\frac{72}{32} = a

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Answer: y = \frac{9}{4}(x + 16)(x + 2)


3 0
3 years ago
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