The value that would make the ratios equal to 4 to 10... I believe it would be 2 to 5
Answer:
1/880
Step-by-step explanation:
The nth term of the geometric sequence is:
an=ar^(n-1)
where
a=first term
r=common ratio
n=nth term
from the question:
120=ar(3-1)
120=ar^2
a=120/(r^2)....i
also:
76.8=ar^(5-1)
76.8=ar^4
a=76.8/r^4.....i
thus from i and ii
120/r^2=76.8/r^4
from above we can have:
120=76.8/r²
120r²=76.8
r²=76.8/120
r²=0.64
r=√0.64
r=0.8
hence:
a=120/(0.64)=187.5
therefore the formula for the series will be:
an=187.5r^0.8
If the preimage point is (5,0) and the image point is (10,0)
then the scale factor is k = 2
Basically the coordinates of the old point have doubled (multiplied by 2)
x = 5 is the old x coordinate
x = 10 is the new x coordinate (5*2 = 10)
y = 0 is the old y coordinate
y = 0 is the new y coordinate (0*2 = 0, no change)
Answer:
1). 
2). 


Step-by-step explanation:
First term of an arithmetic sequence is (-1) and common difference is 5.
Then we have to find twenty fifth term of this arithmetic sequence.
Since explicit formula of an arithmetic sequence is represented by

Where
represents nth term of the sequence.
a = first term
n = number of term
and d = common difference
Now we will find 25th term of this sequence.

= (-1) + 120
= 119
Similarly in second part of this question we have to find first three terms of an arithmetic sequence in which
and

Now from the explicit formula
17 = a + (21 - 1)d
17 = a + 20d --------(1)
75 = a + (50 - 1)d
75 = a + 49d --------(2)
Now we subtract equation 1 from 2
75 - 17 = 49d - 20d
29d = 58
d = 
By putting d = 2 in equation 1
17 = a + 20×2
17 = a + 40
a = 17 - 40
a = -23
Therefore, first three terms of this sequence will be


