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expeople1 [14]
3 years ago
12

Which of the following is the correct equation for the distance formula for the points (x1, y1) and (x2,y2)?

Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

  A. D=sqrt( (x2-x1)^2+(y2-y1)^2 )

Step-by-step explanation:

The distance between two points is the root of the sum of the squares of the differences in their corresponding coordinates. The equation of choice A is the usual formulation.

__

<em>Comment on answer choices</em>

Because the square of a number is the same as the square of its opposite, the formula in choice D is also correct.

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Value that makes the ratios equal<br> 4 to 10, 2 to ?
dalvyx [7]
The value that would make the ratios equal to 4 to 10... I believe it would be 2 to 5
4 0
3 years ago
Share £880 into the ratio of 3:1
Shkiper50 [21]

Answer:

1/880

Step-by-step explanation:

4 0
3 years ago
The third term of a sequence is 120. The fifth term is 76.8. Write an explicit rule representing this geometric sequence.
juin [17]
The nth term of the geometric sequence is:
an=ar^(n-1)
where 
a=first term
r=common ratio
n=nth term
from the question:
120=ar(3-1)
120=ar^2
a=120/(r^2)....i
also:
76.8=ar^(5-1)
76.8=ar^4
a=76.8/r^4.....i
thus from i and ii
120/r^2=76.8/r^4
from above we can have:
120=76.8/r²
120r²=76.8
r²=76.8/120
r²=0.64
r=√0.64
r=0.8
hence:
a=120/(0.64)=187.5
therefore the formula for the series will be:
an=187.5r^0.8
4 0
3 years ago
Read 2 more answers
DO,K = (5, 0) (10, 0) The scale factor is 1/2 2 5
Lapatulllka [165]
If the preimage point is (5,0) and the image point is (10,0)
then the scale factor is k = 2

Basically the coordinates of the old point have doubled (multiplied by 2)

x = 5 is the old x coordinate
x = 10 is the new x coordinate (5*2 = 10)

y = 0 is the old y coordinate
y = 0 is the new y coordinate (0*2 = 0, no change)
3 0
3 years ago
Find the twenty-fifth term of an arithmetic sequence if the first term is-1 and the common difference is 5. Write the first thre
denis-greek [22]

Answer:

1). T_{25}=119

2). T_{1}=-23

T_{2}=-23+2=-21

T_{3}=-23+4=-19

Step-by-step explanation:

First term of an arithmetic sequence is (-1) and common difference is 5.

Then we have to find twenty fifth term of this arithmetic sequence.

Since explicit formula of an arithmetic sequence is represented by

T_{n}=a+(n-1)d

Where T_{n} represents nth term of the sequence.

a = first term

n = number of term

and d = common difference

Now we will find 25th term of this sequence.

T_{25}=(-1)+(25-1)5

= (-1) + 120

= 119

Similarly in second part of this question we have to find first three terms of an arithmetic sequence in which

T_{21}=17 and

T_{50}=75

Now from the explicit formula

17 = a + (21 - 1)d

17 = a + 20d   --------(1)

75 = a + (50 - 1)d

75 = a + 49d --------(2)

Now we subtract equation 1 from 2

75 - 17 = 49d - 20d

29d = 58

d = \frac{58}{29}=2

By putting d = 2 in equation 1

17 = a + 20×2

17 = a + 40

a = 17 - 40

a = -23

Therefore, first three terms of this sequence will be

T_{1}=-23

T_{2}=-23+2=-21

T_{3}=-23+4=-19

8 0
3 years ago
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