Answer:
A. The y-intercept of g(x) is less than the y-intercept of f(x).
Step-by-step explanation:
The x-intercept, or when x = 0, of f(x) is -4, the x-intercept of g(x) is -8, so g(x) are neither greater nor equal to f(x), this marks out C and D. The y-intercept, or when y = 0, is in this case f(x) or g(x). The y-intercept of f(x) is 16, the y-intercept of g(x) is 4, so the y-intercept of g(x) is not equal to the y-intercept of f(x), this marks out B. Now to check A, 4 < 16, so y-intercept of g(x) < y-intercept of f(x), the answer is A
Point <em>A</em> represents the complex conjugate z₁ and point L represents the complex conjugate of z₂ respectively
The complex conjugate of a complex number is a complex number that having equal magnitude in the real and imaginary part as the complex number to which it is a conjugate, but the imaginary part of the complex conjugate has an opposite sign to the original complex number
Therefore, graphically, the complex conjugate is a reflection of the original complex number across the x-axis because the transformation for a reflection of the point (x, y) across the x-axis is given as follows;
Preimage (x, y) reflected across the <em>x</em> axis give the image (x, -y)
Where in a complex number, we have;
x = The real part
y = The imaginary part
The reflection of z₁ across the x-axis gives the point <em>A</em>, while the reflection of z₂ across the x-axis gives the point <em>L</em>
Therefore;
Point <em>A</em> represents the complex conjugate z₁ and point L represents the complex conjugate of z₂
Learn more about complex numbers here;
brainly.com/question/20365080
Use the distributive property.
(3/8)*(16x-24)=(3/8)(16x)-(3/8)(24)
16x*3/8=48x/8=6x
24*3/8=72/8=9
6x+9
Hope this helps!
Answer:
Option 2 - Approximately 24–36 pounds
Step-by-step explanation:
Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.
To find : What range of weights would 99.7% of the dogs have?
Solution :
The range of 99.7% will lie between the mean ± 3 standard deviations.
We have given,
Mean weight of Eskimo dogs is 
Standard deviation of Eskimo dogs is 
The range of weights would 99.7% of the dogs have,
Therefore, The range is approximately, 24 - 36 pounds.
So, Option 2 is correct.
