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svetlana [45]
3 years ago
7

Can somebody please help me? asap

Mathematics
1 answer:
Margarita [4]3 years ago
6 0
Y= 2 slope= -3 this should be right.
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Y=-3 + 3x<br> 3х + 2y = 2
mojhsa [17]
3x+2(3x-3)=2
9x-6=2
9x=8
X=8/9
4 0
2 years ago
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What are whole number dimensions?
Sphinxa [80]
When you get to the point where the width is larger than the length, you can stop because you have exhausted all the possibilities. The greatest area will be the rectangle that is closer in to a square than any of the others.
5 0
3 years ago
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How do you solve systems of equations using matrices? I need help with the steps please
seraphim [82]
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.

6 0
3 years ago
Given that the prime factorisation of 198 is 2x(3×3)x11. State the minimum integer value of
mylen [45]

Answer:

22

Step-by-step explanation:

198 = 2×3²×11

For 198n to be a perfect square, each prime factor must have an even exponent.  So the smallest 198n would be:

198n = 2²×3²×11²

198n = 4356

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7 0
3 years ago
maze going to the lake to visit some friends at the lake is 60 miles away and Renee is driving 40 mph the entire time how long w
mojhsa [17]

Answer:

it will take her an hour and 25 minutes roughly

Step-by-step explanation:

7 0
3 years ago
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