3x+2(3x-3)=2
9x-6=2
9x=8
X=8/9
When you get to the point where the width is larger than the length, you can stop because you have exhausted all the possibilities. The greatest area will be the rectangle that is closer in to a square than any of the others.
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:
22
Step-by-step explanation:
198 = 2×3²×11
For 198n to be a perfect square, each prime factor must have an even exponent. So the smallest 198n would be:
198n = 2²×3²×11²
198n = 4356
n = 22
Answer:
it will take her an hour and 25 minutes roughly
Step-by-step explanation: