Well we know 4% is just 4/100.
So 20 = 4/100.
Let's find out what 1/100 is and multiply that by 100:
20/4 = 5.
So 1/100 = 5.
5*100 = 500.
Step-by-step explanation:
Put the values of x = 6, y = -7 and z = 0.8 to the expressions:
a) 5x → 5(6) = 30
b) 3y → 3(-7) = -21
c) 10z → 10(0.8) = 8
Answer:
Part of work left to finish after two work hours is 7/20
Step-by-step explanation:
Firstly, we need to calculate their joint work rate
That will be;
1/(1/5 + 1/8) = 1/(13/40) = 40/13
This means that they will complete the task in 40/13 hours
1 whole part takes 40/13
x part will take 2 hours
x * 40/13 = 2
40x = 26
x = 26/40
So the part that will be completed in two hours is 26/40
This means that the part left to complete will be:
1 - 26/40 = 14/40 = 7/20
Answer:
y = -1x + 3 or f(x) = -1x + 3
Step-by-step explanation:
Rise/run = 3/-3 =<em> <u>-1</u></em>
Crosses the y-axis at <em><u>3</u></em>
y = <em><u>-1</u></em>x + <em><u>3</u></em> or f(x) = <em><u>-1</u></em>x + <em><u>3</u></em>
First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
