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Marizza181 [45]
3 years ago
14

Scientists want to know the total trout population in a part of Lake Michigan. They tagged and released 200 trouts back into the

wild. Later, they found 60 trouts in that same part of Lake Michigan, 10 of which were tagged. Estimate the total trout population in that part of Lake Michigan to the nearest whole number.
Mathematics
1 answer:
blondinia [14]3 years ago
6 0
The estimate would be 1200.

We will set up a proportion for this.  10 out of 60 of the sample were tagged, so that is the first ratio.  The 200 that were tagged would be in the numerator of the second ratio (10 was the portion tagged, and 200 is the portion tagged, so they both go on top).  We do not know the total number so we use a variable:

10/60 = x/200

Cross multiply:

10*x = 60*200
10x = 12000

Divide both sides by 10:
10x/10 = 12000/10
x = 1200
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75+20 1X -40+13 X +76 + 3X -20 = 720 solve for x
hoa [83]
Thanks.

Answer is 37x=720-20+20-75-76+40=609

x=609/37= 16.459 Assuming all the numbers are the same as we can see it in the equation.
4 0
4 years ago
Suppose that you are conducting a survey on how many students have blue eyes in each first period classroom at Garfield Middle s
rusak2 [61]

Answer:

  • <u>The correct statement is the first one: </u><u><em>The number of blue-eyed students in Mr. Garcia's class is 2 standard deviations to the right of the mean</em></u><em> </em>

<em />

Explanation:

To calculate how many<em> standard deviations</em> a particular value in a group is from the mean, you can use the z-score:

      z-score=(x-\mu )/\sigma

Where:

  • z-score is the number of standard deviations the value of x is from the mean
  • \mu  is the mean
  • \sigma  is the standard deviation

Substitute in the formula:

       z-score=(10-6)/2=4/2=2

Which means that <em>the number of blue-eyed students in Mr. Garcia's class is 2 standard deviations</em> above the mean.

Above the mean is the same that to the right of the mean, because the in the normal standard probability graph the central value is Z = 0 (the z-score of the mean value is 0), the positive values are to the right of the central value, and the negative values are to the left of the central value.

Therefore, the correct statement is the first one: <em>The number of blue-eyed students in Mr. Garcia's class is 2 standard deviations to the right of the mean, </em>

4 0
4 years ago
Consider three events A, B and C with following properties.
lisov135 [29]
By the inclusion/exclusion principle,

\mathbb P(D)=\mathbb P(A\cup B\cup C)
\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)
\mathbb P(D)=\dfrac14+\dfrac16+\dfrac14-\dfrac39+\dfrac1{13}
\mathbb P(D)=\dfrac{16}{39}\neq1

So the union of A, B, and C does not constitute the entire sample space.
5 0
3 years ago
Line 1 passes through the points -2,7 and 3,3. Line 2 passes through the points 5,1 and 9,1. Find the slope of each line. Which
RSB [31]

Answer:

The slope of the given line 1 is  -4/5.

The slope of the given line 2 is  0.

The line 2 has a greater slope then line 1.

Step-by-step explanation:

The slope of a line with points (x1,y1) and (x2,y2) is given as:

m = \frac{y_2- y_1}{x_2-x_1}

Now, Here the, points of the line 1 are A (-2,7) and B (3,3)

So, here, the slope of line AB  is m = \frac{3 -7}{3-(-2)}  = \frac{-4}{3 +2} =   \frac{-4}{5}

Hence, the slope of the given line 1 is  -4/5.

Now, Here the, points of the line 2 are P (5,1) and Q (9,1)

So, here, the slope of line PQ  is m = \frac{1-1}{9-5}  = \frac{0}{4} =   0

Hence, the slope of the given line 2 is  0.

Now, as we can see  0    >  ( -4 / 5)

So, the line 2 has a greater slope then line 1.

5 0
3 years ago
Haley draws a picture to show 8 / 2 which picture could be Haley's
goldfiish [28.3K]

Answer:

..   ..

..   ..

Step-by-step explanation:

8/2=4

6 0
3 years ago
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