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3 years ago

Please help this is the easiest question ever.

Mathematics

2 answers:

Elodia [21]3 years ago

8 0

The answer to this question is 22

Vlad1618 [11]3 years ago

5 0

Answer:

3 3/13, 1 29/13 and, 42/13

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Just need some help with the second answer thanks :)

vazorg [7]

Answer:

4,151,347,200

Step-by-step explanation:

To find how many ways the train can be made up we use the permutation formula and the values given.

n = 16

k = 9

$_{n}P_{k}=\dfrac{n!}{(n-k)!}$

$_{16}P_{9}=\dfrac{16!}{(16-9)!}$

$_{16}P_{9}=\dfrac{16!}{7!}$

$_{16}P_{9}=4,151,347,200$

So there will be 4,151,347,200 different ways that the train can be made.

5 0

4 years ago

The equation d=4 -1/15t represents your distance from home,d, for each minute you walk,t. If you graphed this equation, determin

Readme [11.4K]

we have

$d=4 -\frac{1}{15}t$

using a graph tool

see the attached figure

For t=0 d=4 -------> the y-intercept

that means that at the time t=0 the house was four units away.

For t=60 min d=0 -------> x-intercept

that means he was already at home at the time t=60 minutes.

therefore

the graph of this equation represents the walk towards the house

3 0

3 years ago

60 pOINTS HELP PLEASE 4. A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5

Solnce55 [7]

K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE
$ke = 0.5 \times 20 \times {5}^{2} \\ ke = 10 \times 25 \\ ke = 250 \: joules$
$gpe = 20 \times 9.81 \times 2 \\ gpe = 40 \times 9.81 \\ gpe = 392.4 \: joules$
g is taken as 9.81

6 0

3 years ago

Answer the following true or false. Justify your answer.

Anna007 [38]

Answer:

a) False b) False c) True d) True e) True

Step-by-step explanation:

a) If A is a subset of B, and x∈B, then x∈A. False

Suppose A is Z (Set of Integers), and B is R (Set of Real Numbers). Then A is a subset of B. x ∈ B, let's say x equals π. If x ∈ B (B = Real Numbers) and x=π then x ∉ A (Z).

We could call A, any other subset of Real numbers (Q, I,..) and we both would come up to the same conclusion when it comes to Real numbers the Set.

So this conclusion is False. Not always an element of a subset is an element of a set.

b) False

For this one, I've drawn some lines, and it is useful to work with them.

Given the set {(x,y) ∈ R²| 0<x<0} then all negative and positive numbers but zero belong to this set.

c) If A and B are square matrices, then AB is also square. True

Taking into account the rules for multiplying matrices. The number of columns of A must be the same number of lines of B to there can be a matrix product.

Whenever we multiply square matrices, we'll always get square matrices. Then this conclusion is true.

d) A and B are subsets of a set S, then A∩B and A∪B are also subsets of S. True

Suppose A= Z (Integer Numbers) and B=Q (Rational Numbers) and S= R (Real Numbers)

A∩B = Z∩Q=∅ and A∪B =Z∪Q = subset

Since the ∅ empty set ⊂ in every set and ZUQ is another Subset of R this is a True conclusion.

e) True. For a matrix A, we define A²= AA

For any Power of Matrices, all we have to do is multiply any given matrix by itself for a given number of times.

M²=M*M

M³=M*M*M